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sukhopar [10]
3 years ago
11

As a shuttle bus comes to a normal stop, it slows from 9.00 m/s to 0.00 m/s in 5.00 s find the acceleration of the bus.

Physics
1 answer:
joja [24]3 years ago
7 0

Answer:

-1.8 m/s^2

Explanation:

vf-vi/t  

0-9=-9

-9/5 = -1.8

-1.8 m/s^2

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Interactive LearningWare 8.1 reviews the approach that is necessary for solving problems such as this one. A motorcyclist is tra
STALIN [3.7K]

Answer:

The angular displacement of each wheel is 269.92 rad

Explanation:

Given:

Angular acceleration \alpha = 6.10 \frac{rad}{s^{2} }

Time to pass cyclist t = 4.36 s

Angular velocity \omega _{f} = 75.2 \frac{rad}{s}

According to the equation of kinematics,

  \omega _{f} = \omega _{i} + \alpha   t

   \omega _{i} = \omega _{f} - \alpha   t

   \omega _{i} = 75.2 - 6.10 \times 4.36

  \omega _{f} = 48.60 \frac{rad}{s}

For finding angular displacement,

    \omega _{f} ^{2}  - \omega _{i} ^{2}  = 2 \alpha  \theta

Where \theta = angular displacement,

  \theta  = \frac{\omega _{f}^{2} - \omega _{i} ^{2}  }{2\alpha }

  \theta  = \frac{5655.04 - 2361.96  }{2\times 6.10 }

  \theta = 269.92 rad

Therefore, the angular displacement of each wheel is 269.92 rad

8 0
3 years ago
How many moles of N2O5 are needed to produce 7.90 g of NO2 <br><br> 2N2O5 = 4NO2 + O2
Furkat [3]
From the chemical eqn 
No of moles of N2O5 = Mass/ molar mass 
Molar mass = (14* 2) + (16 *5) = 28 + 90 = 118g. 
From the chemical equation 7.9g of NO2 reacts with 7.9 *2 g of N2O5. We have a 1 :2 mole ratio. Hence mass of N2O5 = 14.8g 
No of moles = 14.8/ 118 = 0.133 moles.
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There's supposed to be a blank in the statement, where the answer is supposed to be inserted.

The question is supposed to say: "A wave is a disturbance that carries ______ from one place to another through matter or space".

To answer the question, write the word "<em>energy</em>" in the blank.

4 0
3 years ago
A tank has the shape of an inverted circular cone with height 16m and base radius 3m. The tank is filled with water to a height
rewona [7]

Answer:

W=17085KJ

Explanation:

From the question we are told that:

Height H=16m

Radius R=3

Height of water H_w=9m

Gravity g=9.8m/s

Density of water \rho=1000kg/m^3

Generally the equation for Volume of water is mathematically given by

 dv=\pi*r^2dy

 dv=\frac{\piR^2}{H^2}(H-y)^2dy

Where

   y is a random height taken to define dv

Generally the equation for Work done to pump water is mathematically given by

 dw=(pdv)g (H-y)

Substituting dv

 dw=(p(=\frac{\piR^2}{H^2}(H-y)^2dy))g (H-y)

 dw=\frac{\rho*g*R^2}{H^2}(H-y)^3dy

Therefore

 W=\int dw

 W=\int(\frac{\rho*g*R^2}{H^2}(H-y)^3)dy

 W=\rho*g*R^2}{H^2}\int((H-y)^3)dy)

 W=\frac{1000*9.8*3.142*3^2}{9^2}[((9-y)^3)}^9_0

 W=3420.84*0.25[2401-65536]

 W=17084965.5J

 W=17085KJ

 

'

'

4 0
3 years ago
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