A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If the disk starts from rest and is then brought in contact with a spinning rubber wheel, we observe that the disk gradually begins to rotate too. If after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 4.0 rad/s, find the average angular acceleration that the disk experiences. (Assume the positive direction is in the initial direction of rotation of the disk. Indicate the direction with the sign of your answer.)
Assume after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 11.0 rad/s.
Answer:
385 rad
Explanation:
The expression for the angular acceleration of a disk that is in contact with a spinning wheel can be given as:
where 
= 
Angular displacement of a disk can be calculated by using the formula:
substituting 11.0 rad/s for 
and t = 35 s ; we have:
Answer:
it is a.health record documentation
Explanation:hope this helps
Answer:
B. Decrease the plane’s speed and height
Explanation:
Decrease in speed of plane:
When the speed of the plane is decreased then initial velocity of the package will be lesser. As a result, final velocity will also be lesser because in this case final velocity depends upon the initial velocity.
Decrease in height:
According to law of conservation of energy:
Loss in potential energy = Gain in Kinetic energy
mgh = ½ mV^2
It means with the decrease in height less potential energy will be converted to kinetic energy. As package has constant mass so it will gain less velocity.
Answer:
the work done by a person is 1,732 J
Explanation:
The computation of the work done by a person is as follows;
The following information is given
Force = 200.N
Distance = 10.0 meters
Angle = 30 degrees
based on the above information
Work done is
Work done is
= (200) (cos 30 degrees) (10.0 meters)
= 1,732 J
hence, the work done by a person is 1,732 J
The same is considered and relevant
The correct answer to the question is B) 5,700 years.
EXPLANATION:
Before going to answer this question, first we have to understand half life period of a radio active substance.
The half life period ![[\ T_{1/2}\ ]](https://tex.z-dn.net/?f=%5B%5C%20T_%7B1%2F2%7D%5C%20%5D)
of a radio active substance is defined as the time in which half of the radio active specimen has undergone decay.
As per the question, the initial concentration of the radioactive carbon-14 is given as 10,000.
Hence, initial concentration 
.
After 5,700 years, the remaining radio active specimen is 5000. It means that half of the radio active specimen has undergone decay in 5,700 years.
Hence, half life period of the radio active carbon-14 specimen is 5,700 years.
