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andre [41]
3 years ago
5

How many solutions does the following equation have? -14(z-5)=-14x+70

Mathematics
1 answer:
zavuch27 [327]3 years ago
4 0

Answer:

Infinite amount of solutions

Step-by-step explanation:

Parallel lines have no solution

Same lines have infinite solutions

Intersecting lines have 1 solution

Step 1: Write out equation

-14(x - 5) = -14x + 70

Step 2: Distribute -14

-14x + 70 = -14x + 70

Here we see that we have 2 exact same lines. Therefore, we have infinite amount of solutions.

Alternatively, we can plug in any number <em>x </em>and it would work. So then we would have infinite amount of solutions as well.

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Answer:

37

Step-by-step explanation:

Using order of operations, multiplication is done before addition.

given

7 + 5 × 6 ← perform multiplication

= 7 + 30 ← do the addition

= 37

8 0
3 years ago
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(a^2-4)(9-b^2)+24ab
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3 years ago
Pencils come in packages of 10.Erasers come in packages of 12. Phillips wants to purpose the smallest number of pencils and eras
balandron [24]

Answer:

The answer to your question is:

Packages of pencils = 6

Packages of erasers = 5

Step-by-step explanation:

Data

Pencils = 10/package

Erasers = 12 / package

Process

Find the least common factor of 10 and 12

                                    10     12     2

                                     5       6     2

                                     5       3     3

                                     5        1    5

                                      1

LCF = 2 x 2 x 3 x 5 = 60

Finally divide 60 by the number of pencils or erasers in each package

Packages of pencils = 60/10 = 6

Packages of erasers = 60/12 = 5

                                                 

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2 years ago
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Answer:

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Step-by-step explanation:

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