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3 years ago

How many solutions does the following equation have? -14(z-5)=-14x+70

Mathematics

1 answer:

zavuch27 [327]3 years ago

4 0

Answer:

Infinite amount of solutions

Step-by-step explanation:

Parallel lines have no solution

Same lines have infinite solutions

Intersecting lines have 1 solution

Step 1: Write out equation

-14(x - 5) = -14x + 70

Step 2: Distribute -14

-14x + 70 = -14x + 70

Here we see that we have 2 exact same lines. Therefore, we have infinite amount of solutions.

Alternatively, we can plug in any number <em>x </em>and it would work. So then we would have infinite amount of solutions as well.

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bonufazy [111]

Answer:

Step-by-step explanation:

7 0

3 years ago

he marketing research department at the Fresno Mall plans to survey teenagers about a newly developed soft drink. Each person sa

Nat2105 [25]

50% of those who liked orange flavored soda also like lime flavored soda according to the conditional probability.

According to the statement

we have given that the in the survey 70% of the people surveyed said they like the orange flavored soda and 35% of the people surveyed said they liked the orange flavored soda AND the lime flavored soda.

And we have to find the conditional probability about this given statement.

So, We know that the

Let A and B represents the following events.

A : The people like the orange flavored soda.

B : The people like the lime flavored soda.

It is given that 70% of the people surveyed said they like the orange flavored soda.

so, P(A) = 0.70

And 35% of the people surveyed said they liked the orange flavored soda AND the lime flavored soda.

So, P(A ∩ B ) = 0.35

A. Conditional probability is a measure of the probability of an event occurring, given that another event has already occurred.

And

B. The formula for conditional probability is is written below:

P(A/B) = P(A ∩ B ) / P (B)

And

C. We need to find the percent of those who liked orange flavored soda also like lime flavored soda.

Use the above written conditional probability formula then

Substitute P(A)=0.70 and P(A∩B)=0.35 in the above formula.

So,

P(B/A) = P(A ∩ B ) / P (A)

P(B/A) = 0.35 / 0.70

P(B/A) = 0.50

So, 50% of those who liked orange flavored soda also like lime flavored soda according to the conditional probability.

Learn more about conditional probability here

brainly.com/question/23382435

Disclaimer: This question was incomplete. Please find the full content below.

Question:

The marketing research department at the Fresno Mall plans to survey teenagers about a newly developed soft drink. 70% of the people surveyed said they like the orange flavored soda. 35% of the people surveyed said they liked the orange flavored soda AND the lime flavored soda. Using this information and the Text Editor, answer the following questions:

1.What is conditional probability?

2.Explain the formula for conditional probability.

3.Explain how to solve this example.

What percent of those who liked orange flavored soda also like lime flavored soda, and how did you come to that conclusion?

#SPJ4

5 0

2 years ago

How do you solve his with working

AlexFokin [52]

Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

$\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888$

b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.

$\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884$