Answer:
Explanation:
From the question we are told that:
Mass of mixture
Mass of Barium
Equation of Reaction is given as
Generally the equation for Moles of Barium is mathematically given by
Since
Therefore
Generally the equation for Mass of Barium is mathematically given by
Therefore
Wavelength= velocity/frequency
wavelength= (3.0 x 10^8m/s) / 7.5 x 10^12 Hz)
you can do the math
I am assuming u that 108 is 10^8 and the 1012 is 10^12
Pulmonary ventilation, and carbonic acid-bicarbonate buffering system
Answer:
Hello
you're answer should be E.HOCH2CH2OH
hope this answer is correct
The limiting reagent will be Al
<h3>What are limiting reagents?</h3>
They are reagents that limit the quantity of products that are formed in reactions.
From the equation of the reaction:
The mole ratio of Al to O2 is 4:3.
With 2 moles of Al and 2 moles of O2, Al becomes limiting while O2 is in excess.
With 2 moles of O2, the amount of Al required should be:
2 x 4/3 = 2.67 moles.
With 2 moles of Al, the amount of O2 required should be:
2 x 3/4 = 1.5 moles
Thus, O2 is in excess by 0.5 moles.
More on limiting reagents can be found here: brainly.com/question/11848702
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