Answer:
false. acids do not neutralize bases.
Explanation:
The answer is: 1.5 moles of oxygen are present.
V(O₂) = 33.6 L; volume of oxygen.
p(O₂) = 1.0 atm; pressure of oxygen.
T = 0°C; temperature.
Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).
At STP one mole of gas occupies 22.4 liters of volume.
n(O₂) = V(O₂) ÷ Vm.
n(O₂) = 33.6 L ÷ 22.4 L/mol.
n(O₂) = 1.50 mol; amount of oxygen.
It's probably animal if that's what's you're asking.
Answer:
35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.
Explanation:
..[1]
Heat of vaporization of acetic acid = 
..[2]
Heat of fusion of acetic acid = 
Heat of sublimation of acetic acid = 
..[3]
[1] + [2] = [3] (Hess's law)


35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.