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PilotLPTM [1.2K]
2 years ago
12

What is the ratio of hydrogen molecules to ammonia molecules in the following reaction

Chemistry
1 answer:
Setler [38]2 years ago
8 0
Chckfincb. For Ingrid t
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In a chemical reaction, substrate molecule A is broken down to form one molecule of product B and one molecule of product C. The
MAVERICK [17]

Answer:

The answer to your question is d. 0.5 M

Explanation:

Data

[A] = 1M

K = 0.5

Concentration of B and C at equilibrium = x

Concentration of A at equilibrium = 1 - x

Equation of equilibrium

                                       k = \frac{[B][C]}{A}

Substitution

                                       0.5 = \frac{[x][x]}{1 - x}

Simplification

                                       0.5 = \frac{x^{2}}{1 - x}

Solve for x

                                      0.5(1 - x) = x²

                                      0.5 - 0.5x = x²

                                       x² + 0.5x - 0.5 = 0

Find the roots             x₁ = 0.5     x₂ = -1

There are no negative concentrations so the concentration of A at equilibrium is  

                       [A] = 1 - 0.5

                             = 0.5 M

4 0
3 years ago
What is used to determine the number of each atom in an ionic formula?
Nutka1998 [239]

the oxidation state of each atom

3 0
3 years ago
Biodiversity is the ___________
riadik2000 [5.3K]

Answer:

answer is 1.A measurment of the...

4 0
2 years ago
What is the molarity of a solution that contains 148g NaOH in 4.00 L solution? a 0.925 M b 0.0253 M c 0.459 M d 1.363 M
Anton [14]

Answer:

M = 0,925

Explanation:

n= mass/Molecular Weight

n = 148g / 39,99 (g/mol)

n= 3,7mol

M= n/Volumen(L)

M= 3,7mol/4L

M=0,925

8 0
3 years ago
Formulate the sequence of steps needed to prepare 250.0 mL of a 0.005 M aqueous solution from solid KMnO4 and pure water.
S_A_V [24]

Answer:

Molarity is a unit that measures how much moles of solute dissolved in a liter of solvent. Molarity expressed using capital M while molarity, a different unit, expressed using lower case m.  

We want to make 0.005 M solution which means we need 0.005 moles of KmnO4 per liter of water. First, we have to calculate how many grams of KMnO4 we need for the solution.

We want to make 250ml solution, so the number of moles of KMnO4 we need will be:  0.005 mol/liter *(250 ml * 1liter/1000ml)= 0.005 mol/liter  * 1/4 liter = 0.00125 moles

The molecular mass of KMnO4 is 158g/mol, so the mass of KMnO4 we need will be:  0.00125 moles *  158g/mol=  0.1975 grams

We know that we need 0.1975 g of KMnO4, now we weigh them and put it inside a dish. After that, we prepare Erlenmeyer or a volumetric flask filled with water half of the volume needed(125ml). Pour the weighted solute into the flask, stir until all solute dissolved.

Then we add water to the container slowly until its volume reaches the 250ml mark.

3 0
2 years ago
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