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vichka [17]
3 years ago
14

If a cylinder holds a volume of 100 cm3, and is 30 cm tall, which is the area of the bottom of the cylinder?

Chemistry
1 answer:
stira [4]3 years ago
4 0
3.33cm squared is the answer
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Three factors that affect the solubility of a substance are pressure, the type of solvent, and volume.
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Hydrogen cyanide, HCN, can be made by a two-step process. First, ammonia reacts with O2 to give nitric oxide, NO.
stealth61 [152]

Answer:

The mass of HCN is 79.65 g.

The mass of reactant which remain at the end of both reactions is 88.5 g.

Explanation:

Given that,

Mass of ammonia = 50.2 g

Mass of methane = 48.4 g

Hydrogen cyanide, HCN, can be made by a two-step process

Ammonia reacts with O₂ to give nitric oxide NO.

The reaction is,

4NH_{3}+5O_{2}\Rightarrow 4NO+6H_{2}O

We need to calculate the mole of NO

Using given data,

2.25 g NH_{3}=\dfrac{50.2}{17}= 2.95\ mole\ NH_{3} [/tex]

4\ mole NH_{3}\ glose 4\ mol NO

2.95 mol NH₃ will produced 2.95 mol NO

Then nitric oxide reacts with methane,

The reaction is,

2NO+2CH_{4}\Rightarrow 2HCN+2H_{2}O+H_{2}

We need to calculate the mole of methane

Using given data,

mole\ of\ methane=\dfrac{48.4}{16}

mole\ of\ methane = 3.03\ moles

2 mole NO produced 2 mole HCN

2.95 mol NO will produced \dfrac{2.95\times3.03}{3.03}= 2.95 mol HCN

We need to calculate the mass of HCN

Using formula of mass

m=N\times M

Where, N = number of mole

M = molecular mass

Put the value into the formula

m=2.95\times27

m= 79.65\ g

The mass of HCN is 79.65 g.

We need to calculate the mass of NO

Using formula of mass

m=N\times M

Where, N = number of mole

M = molecular mass

Put the value into the formula

m=2.95\times30

m= 88.5\ g

Hence, The mass of HCN is 79.65 g.

The mass of reactant which remain at the end of both reactions is 88.5 g.

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Which statement best describes an array of 10 elements where the elements are of a class type?
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The array will be created with the elements equal to null.
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0.0136 g + 2.70 × 10-4 g - 4.21 × 10-3 g = ?
melisa1 [442]

Answer choice is , 2

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