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Yuki888 [10]
3 years ago
13

: Consider a transformer used to recharge rechargeable flashlight batteries, that has 500 turns in its primary coil, 4 turns in

its secondary coil, and an input voltage of 120 V Randomized Variables 33% Part (a) What is the voltage output?Part (b) What input current,, in milliamps, is required to produce a 3.6 A output current? là 33% Part (c) What is the power input, in watts?
Physics
1 answer:
Aneli [31]3 years ago
8 0

Answer:

a) 096V  b) 0.0288A  c) 0.3456W

Explanation:

a) Vp/Vs= Np/Ns

 120/Vs= 500/4

Vs= 096V

b) Np/Ns= Is/Ip

500/4= 3.6/Ip

Ip= 0.0288A

c) P= VI

P=(120)(0.0288)

P= 0.3456W

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