Answer:
Yes, we must focus on p-value along with the alpha level
Explanation:
Alpha and P values are provides two different set of information. While on one hand alpha values sets an extreme value set before rejecting the hypothesis, P value determines the extremeness of the values in the data set. Thus, if p values is lesser than or equal to alpha value, the null hypothesis is rejected, If p value is greater than alpha value, then the null hypothesis is not rejected.
<span>When Sodium moves into the neuron it causes a charge change in the neuron, making it very positive. It repolarizes by pumping sodium back out of the neuron, re-establishing the potential. Neurotransmitters transmit an impulse from one neuron to another chemically. Inhibitory neurotransmitters stop impulses, excitatory neurotransmitters create and encourage impulses. For an action potential to fire the threshold of the input source must be reached.</span>
Answer:
10 seconds
Explanation:
We have the equation V = at (speed = acceleration x time)
We want to find the time, so can rearrange to T = V/a (time = speed / acceleration).
From the question, we know V is 5 and a is 0.5.
Now we can substitute that into our equation: 5/0.5 = 10.
So the time is 10 seconds.
Hope this helps! Let me know if you have any questions :)
Here is the answer to the given question above. If Angela has been feeling fatigued and a test is used to check the basal metabolic rate and revealed that she has a low metabolic rate, therefore, the possible diagnosis for Angela would be HYPOTHYROIDISM. <span>The BMR test works by precisely measuring the amount of oxygen that you consume when your body is basal, or completely at rest. Hope this answers your question.</span>
Initial volume of mercury is
V = 0.1 cm³
The temperature rise is 35 - 5 = 30 ⁰C = 30 ⁰K.
Because the coefficient of volume expansion is 1.8x10⁻⁴ 1/K, the change in volume of the mercury is
ΔV = (1.8x10⁻⁴ 1/K)*(30 ⁰K)(0.1 cm³) = 5.4x10⁻⁴ cm³
The cross sectional area of the tube is
A = 0.012 mm² = (0.012x10⁻² cm²).
Therefore the rise of mercury in the tube is
h = ΔV/A
= (5.4x10⁻⁴ cm³)/(0.012x10⁻² cm²)
= 4.5 cm
Answer: 4.5 cm
