Answer:
c,-0.45 ,
e. 1.16
g. 5/3
h. √2
Cannot be probability.
Step-by-step explanation:
Probability of any occurrence is always in the interval of 0 to 1. 0 and 1 inclusive.
0≤P(A)≤1
Any value outside this boundaries cannot be probability.
Therefore, -0.45,1.16,5/3 and √2 cannot be probability.
If the given differential equation is

then multiply both sides by
:

The left side is the derivative of a product,
![\dfrac{d}{dx}\left[\sin(x)y\right] = \sec^2(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%3D%20%5Csec%5E2%28x%29)
Integrate both sides with respect to
, recalling that
:
![\displaystyle \int \frac{d}{dx}\left[\sin(x)y\right] \, dx = \int \sec^2(x) \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%5C%2C%20dx%20%3D%20%5Cint%20%5Csec%5E2%28x%29%20%5C%2C%20dx)

Solve for
:
.
There is no list and no choices given.
The solutions of | x | = 10 are x = 10 and x = -10 .
All (both) solutions happen to be integers.
There are no other solutions.
Answer:
(b) 0.30 atm
Step-by-step explanation:
Given data
Initial pressure= 1.2atm
Initial volume= 1.0L
Final volume= 4.0L
Final pressure= ???
Let us apply the gas formula to find the Final pressure
P1V1= P2V2
Substitute
1.2*1= x*4
Divide both sides by 4
1.2/4= x
x= 0.3atm
Hence the final pressure is 0.3 atm