The answer is the circled number in the box hope this helps sss
Given: In ΔDEF and ΔDGF, Side DF is common.
To prove congruent of the triangle, we must require the minimum three conditions; like two sides and one angle of one triangle should be equal to the other triangle. OR Three sides of one triangle should be equal to the other triangle. OR Two angles and one side of one triangle should be equal to the other triangle. etc.
As per given question, to prove congruent of given triangles by SAS property then we should have given two sides and one angle of one triangle should be equal to the other triangle as additional information.
Since, In ΔDEF and ΔDGF, Side DF is common. So, we should require only one side and one angle that should be equal to another triangle.
Answer:
use identity (a - b) ^3 = a^3 - b^3 - 3ab (a - b)
here, a = x ^2
b = -1
= (x^2)^3 - (-1)^3 - 3 * x ^2 * -1 ( x^2 - (-1) )
x^6+ 3 x^2 ( x ^2 + 1)
I think this is the answer
I think it’s 0.28
I hope that helped
Answer:
A. GCF(a,b) = 
B. LCM(a,b) = 
Step-by-step explanation:
The GCF of two or more integers is their greatest common factor. In order to find it, you must factorise them first and then do the product of the factors that appear in all the factorisations, with their least exponent.
Hence, the GCF of 
and 
is .
The LCM of two or more integers is their least common multiple. In order to find it, you must factorise them first and then do the product of the multiples that appear in one or all the factorisations, with their greatest exponent.
Hence, the LCM of and is
