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2 years ago

9

How do you multiply fractions by improper fractions

1 answer:

katovenus [111]2 years ago

4 0

Well you have to Multiply the numerators together and then <span>Multiply the denominators together after that you simplify </span><span>Convert the improper fraction (if it is improper) to a mixed fraction answer. To do this divide the denominator into the numerator finding the quotient and remainder.</span>the fraction and then

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Determine if the equation has no solution,one solution, or infinite many solution.

Vladimir [108]

Answer:

Step-by-step explanation:

-2(11-12)=-4(1-6x) becomes -2(-1) = -4(1 - 6x)

Next, we divide both sides by -2, obtaining -1 = 2(1 - 6x), and then

-1 = 2 -12x, or

-3 = -12x

Simplifying this result, we get 1 = 4x, or x = 1/4

We conclude that -2(11-12)=-4(1-6x) has ONE solution, which is x = 1/4

3 0

2 years ago

Jael has a monthly budget of x dollars. She spends $1,500 on her mortgage every month. One-fourth of her remaining budget is spe

Alecsey [184]

Answer:

B. y=(x-1500)/4

Step-by-step explanation:

Given that:

Monthly budget = x dollars

Monthly mortgage = $1500

Recreational activities = 1/4 of remaining budget

Amount in dollar spent on recreational activities =

(Monthly budget - monthly mortgage) * 1/4

(x - 1500) * 1/4

Hence,

y = (x - 1500) / 4

5 0

2 years ago

Find the missing side lengths. Leave your answers as radicals in simplest form. Please help!! Due today

Nataly_w [17]

Answer:

$m = 10\sqrt 3$

$n = 10$

Step-by-step explanation:

Required

Find m and n

Considering the given angle, we have:

$\sin(60) = \frac{Opposite}{Hypotenuse}$

This gives:

$\sin(60) = \frac{m}{20}$

Make m ths subject

$m = 20 * \sin(60)$

$\sin(60) =\frac{\sqrt 3}{2}$

So, we have:

$m = 20 *\frac{\sqrt 3}{2}$

$m = 10\sqrt 3$

Considering the given angle again, we have:

$\cos(60) = \frac{Adjacent}{Hypotenuse}$

This gives:

$\cos(60) = \frac{n}{20}$

Make n the subject

$n = 20 * \cos(60)$

$\sin(60) =\frac{1}{2}$

So, we have:

$n = 20 *\frac{1}{2}$

$n = 10$

5 0

2 years ago

What is the range of the function y=2sin x

statuscvo [17]

take the absolute value of the coefficient (2)

then the lower bound is the negative of that (-2)

so the range is [-2,2]

7 0

2 years ago

Read 2 more answers

Rewrite in simplest terms: 3h - 2(-0.1h - 0.8)<br>please help

levacccp [35]

Answer:

3.2h+1.6

Step-by-step explanation:

3h-2(-0.1h-0.8)

3h+0.2h+1.6

3.2h+1.6

8 0

2 years ago