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3 years ago

15

Line segments XY and TU are parallel to each other. Line segment AB is also parallel to TU. Therefore, line segments XY and AB a

re parallel to each other. true or false

1 answer:

Advocard [28]3 years ago

8 0

That would be true...XY and TU and AB are all parallel

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Two numbers have a sum of 18, and 4 times the first number minus the second number is equal to 17. What is the smallest number?

sammy [17]

Answer:

The smallest number is 7

Step-by-step explanation:

Using simultaneous equation;

x+y = 18.....(1)

4x-y = 17.....(2)

from equation (1)..

x+y = 18

y = 18-x...(3)

substitute y into equation (2)

4x-y = 17

4x-(18-x) = 17

4x-18+x = 17

4x+x = 17+18

5x = 35

x = 35÷5

x = 7

substitute x into equation (3)

y = 18-x

y = 18-7

y = 11

Therefore; x=7

y=11

11+7=18

(4×7)-11=17

the smallest number is 7

4 0

3 years ago

3^3 times 3^3 divides by 3^4 <br><br> 3^0 <br>3^1 <br>3^2 <br>3^4

USPshnik [31]

Answer:

3^2

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)/(a^c) = a^(b-c)

__

$\dfrac{(3^3)(3^3)}{(3^4)}=3^{3+3-4}=\boxed{3^2}$

8 0

3 years ago

Read 2 more answers

Peter bought 5 pens and 8 pencils they cost him 13,25€. How much does one pencil and one Pen cost if the pencil 1,35€ cheaper th

Amanda [17]

Step-by-step explanation:

pen=1.35 + pencil......1

5pen+8pencil=13.5 calculate this for pen

pen=13.5-8pencil/5.....2 combine equation 1$2

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3 years ago

Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Tom [10]

Stokes' theorem says the integral of the curl of $\vec F$ over a surface $S$ with boundary $C$ is equal to the integral of $\vec F$ along the boundary. In other words, the flux of the curl of the vector field is equal to the circulation of the field, such that

$\displaystyle\iint_S\nabla\times\vec F\cdot\mathrm d\vec S=\int_C\vec F\cdot\mathrm d\vec r$

We have

$\vec F(x,y,z)=x^2\,\vec\imath+4x\,\vec\jmath+z^2\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=4\,\vec k$

Parameterize the ellipse $S$ by

$\vec s(u,v)=\dfrac{u\cos v}{\sqrt5}\,\vec\imath+\dfrac{u\sqrt5\sin v}4\,\vec\jmath$

with $0\le u\le1$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

$\dfrac{\partial\vec s}{\partial\vec u}\times\dfrac{\partial\vec s}{\partial\vec v}=\dfrac u4\,\vec k$

Then the flux of the curl is

$\displaystyle\iint_S4\,\vec k\cdot\dfrac u4\,\vec k\,\mathrm dA=\int_0^{2\pi}\int_0^1u\,\mathrm du\,\mathrm dv=\boxed{\pi}$

4 0

3 years ago

Someone help me!!!Please no links

adell [148]

Answer:

I will answer this for you and the links are so annyoing fr

Step-by-step explanation:

give me a couple of minutes to figure it out then I will post the answer!

5 0

2 years ago