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Afina-wow [57]
3 years ago
6

In active transport, a. vesicle inside the cell fuses with the plasma membrane and releases its contents outside the cell. b. th

e plasma membrane forms a pocket that pinches inward, forming a vesicle that contains material from outside the cell. c. molecules move across the plasma membrane by crossing the lipid bilayer directly, rather than by using a transport protein. d. molecules move across the plasma membrane against their concentration gradient. e. no energy input is required from the cell.
Biology
1 answer:
Vlad [161]3 years ago
7 0

Answer:

Option (d).

Explanation:

Active transport is used for the transportation of the molecules through the plasma membrane. The active transport requires energy in the form of ATP from molecules transport.

The molecule moves from their region of the higher concentration to the region of their low concentration. The substances involved in the active transport move against their concentration gradient and requires an energy input.

Thus, the correct answer is option (d).

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Irina18 [472]

Answer:

A serial dilution and the following plating experiment is done in order to determine the actual amount of bacteria/microbes in a specific volume of soil sample. As a standard test, a set volume of the lower dilution is obtained and positioned on a median plate and permitted to increase for the needed amount of time. The amount of colonies is evaluated and thus the overall Colony Forming Units (CFU) is determined by unit volume of the sample plated and therefore the volume of soil sample employed.

Therefore,

The calculation is done using:

CFU/ml = Number of colonies appeared × dilution factor / volume plated

Given,

Number of colonies appeared = 97

dilution factor = 10^(-6)

volume plated = 1/10 = 0.1

This will help us calculate it as:

CFU/ml = 97 * 10^(-6) / 0.1

= 97 * 10^(-7) CFU/ml

This CFU/ml helps determine the amount of bacterial colonies per unit volume of sample plated.

Given,

The original sample as 1g or 1000 mg of soil in its total volume.

Therefore,

The number of bacteria can be calculated using:

Amount of bacteria in original sample

= 97 * 10^(-7) CFU/ml × 1/ 1000 mg

= 9.7 * 10^(-3) CFU/mg

8 0
3 years ago
Help help help please please please
Arturiano [62]

Answer:

c

Explanation:

5 0
3 years ago
What is Anopheles mosquitoes?
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8 0
4 years ago
Which cell structures are seen in prokaryotic and eukaryotic cells?
WINSTONCH [101]
Prokaryotes and eukaryotes are the two different types of cells.
Eukaryotic cells contain membrane-bound organelles, such as the nucleus, endoplasmic reticulum, mitochondria while prokaryotic cells do not but the ribosome is the only organelle that can be seen in both prokaryotic and eukaryotic cells.
Prokaryotic and eukaryotic ribosomes perform the same functions that is protein synthesis, however, eukaryotic ribosomes are much larger than prokaryotic ones.

Thus, the correct answer is option D
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4 years ago
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