The description of jake performing an experiment is your answer
The answer to this question is 1686.
Can you give more context to the question so i can answer it?
Basically your just swapping there positions like so:
if x=-5, then 3-2x=13
Hope this helps! :)
Answer:
![x=\frac{\sqrt{14} }{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B%5Csqrt%7B14%7D%20%7D%7B2%7D)
Step-by-step explanation:
Notice that you are given an isosceles right-angle triangle to solve, since each of its two acute angles measures
. Then such means that the sides opposite to these acute angles (the so called "legs" of this right angle triangle) must also be of the same length (x).
We can then use the Pythagorean theorem that relates the square of the hypotenuse to the addition of the squares of the triangles legs:
![(\sqrt{7})^2=x^2+x^2\\7=2\,x^2\\x^2=\frac{7}{2} \\x=+/-\sqrt{\frac{7}{2}} \\x=+/-\frac{\sqrt{14} }{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7B7%7D%29%5E2%3Dx%5E2%2Bx%5E2%5C%5C7%3D2%5C%2Cx%5E2%5C%5Cx%5E2%3D%5Cfrac%7B7%7D%7B2%7D%20%5C%5Cx%3D%2B%2F-%5Csqrt%7B%5Cfrac%7B7%7D%7B2%7D%7D%20%5C%5Cx%3D%2B%2F-%5Cfrac%7B%5Csqrt%7B14%7D%20%7D%7B2%7D)
We use just the positive root, since we are looking for an actual length. then, the requested side is:
![x=\frac{\sqrt{14} }{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B%5Csqrt%7B14%7D%20%7D%7B2%7D)