All categories

2 years ago

starfish’s top speed is approximately 161 centimeters per minute. What is this speed to the nearest centimeter per second?

Mathematics

2 answers:

EastWind [94]2 years ago

8 0

Answer:

Speed of the Star Fish is 3 centimeter per second.

Step-by-step explanation:

Given:

Top speed of star fish = 161 centimeter per minutes

We need to express given speed in centimeter per second.

We know that ,

1 minute = 60 seconds.

So, Speed of Star fish in centimeter per second = $161\times\frac{1\:cm}{60\:second}$

= $\frac{161}{60}\:\frac{cm}{second}$

= $2.6833\:\frac{cm}{second}$

= $3\:cm\:per\:second$

Therefore, Speed of the Star Fish is 3 centimeter per second.

arlik [135]2 years ago

3 0

There are 60 seconds in 1 minute

$\frac{161}{} \frac{cm}{min} \times \frac{1}{60} \frac{min}{seconds}= \frac{161}{60} \frac{cm}{seconds}$

You might be interested in

Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v

olga_2 [115]

We are given

$f=z^3 -x^2y$

Firstly, we can find gradient

so, we will find partial derivatives

$f_x=0 -2xy$

$f_x=-2xy$

$f_y=0 -x^2$

$f_y=-x^2$

$f_z=3z^2$

now, we can plug point (-5,5,2)

$f_x=-2*-5*5=50$

$f_y=-(-5)^2=-25$

$f_z=3(2)^2=12$

so, gradient will be

$gradf=(50,-25,12)$

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

$|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}$

$|v|=\sqrt{29}$

now, we can find unit vector

$v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

now, we can find dot product to find direction of the vector

$dir=(gradf) \cdot (v')$

now, we can plug values

$dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

$dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })$

$dir=-\frac{248\sqrt{29}}{29}$ .............Answer

7 0

3 years ago

Read 2 more answers

Go step by step to reduce the radical. √216

iris [78.8K]

Answer: 6√6

Step-by-step explanation:

√216=

√(36*6)=6√6

5 0

2 years ago

Find the average velocity of the function over the given interval.

snow_lady [41]

Answer:

Average velocity of the function over the given interval

= $log(\frac{7}{4} ) -2$

Step-by-step explanation:

Explanation:-

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

Average velocity = $\frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx$

= $\frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx$

now integrating

= $\frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )$

= $\frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}$

= $\frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))$

by using formulas

log a-log b = log(a/b)

on simplification , we get

= $\frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)$

= $log(\frac{7}{4} ) -2$

Average velocity of the function over the given interval

= $log(\frac{7}{4} ) -2$

6 0

3 years ago

Can i have help please?

alexandr1967 [171]

The means and medians are not  the same.

3 0

3 years ago

Read 2 more answers

Below are two different functions, f(x) and g(x). What can be determined about their slopes?

worty [1.4K]

<h3>Answer: B) the function g(x) has a larger slope</h3>

===================================================

Explanation:

The slope of f(x) is 4, since the equation y = 4x+2 has slope m = 4. Compare this to y = mx+b.

The slope of g(x) is 5. Note how if we started at (0,-2) on the red line and moved up 5 and to the right 1, we arrive at (1,3) which is another point on the red line. You could use the slope formula

m = (y2-y1)/(x2-x1)

to get the same result.

Since the slope of f(x) is 4 and the slope of g(x) is 5, we see that g(x) has a larger slope. The g(x) line is steeper compared to f(x).

6 0

3 years ago