All categories

2 years ago

starfish’s top speed is approximately 161 centimeters per minute. What is this speed to the nearest centimeter per second?

Mathematics

2 answers:

EastWind [94]2 years ago

8 0

Answer:

Speed of the Star Fish is 3 centimeter per second.

Step-by-step explanation:

Given:

Top speed of star fish = 161 centimeter per minutes

We need to express given speed in centimeter per second.

We know that ,

1 minute = 60 seconds.

So, Speed of Star fish in centimeter per second = $161\times\frac{1\:cm}{60\:second}$

= $\frac{161}{60}\:\frac{cm}{second}$

= $2.6833\:\frac{cm}{second}$

= $3\:cm\:per\:second$

Therefore, Speed of the Star Fish is 3 centimeter per second.

arlik [135]2 years ago

3 0

There are 60 seconds in 1 minute

$\frac{161}{} \frac{cm}{min} \times \frac{1}{60} \frac{min}{seconds}= \frac{161}{60} \frac{cm}{seconds}$

You might be interested in

Krysta's soccer practice started at 7:45 A.M. on Saturday morning. The team practiced dribbling for 15 minutes and practiced sho

Furkat [3]

Total time used= 15+45+30=90 mins

Initial time=7:45

final time will be 1 hr 30 mins more than initial Time

final time= 9:15 am

6 0

2 years ago

Mark wants to paint a mural He has 1 1/8 gallons of yellow and 7/8 of blue. Mark plans to use 3/4 gallon of each paint color. Ho

geniusboy [140]

Answer:

1/4 gallon of yellow of paint and none of the blue paint

Step-by-step explanation:

3 0

2 years ago

Which line in the graph has the equation y= 1/2x + 2

Alexxx [7]

Answer:

Step-by-step explanation:

y= mx +b

b the y-intercept and is 2 so is red or purple line

m is the slope = 1/2 so rise 1 and run 2 is the purple line

4 0

3 years ago

Simplify this: log√24+ log6

Kitty [74]

simplifying $log\sqrt{24}+log6$ we get $log(12\sqrt{6})$

Step-by-step explanation:

We need to simplify: $log\sqrt{24}+log6$

Solving:

Applying the rule:

log a + log b = log(ab)

$log\sqrt{24}+log6\\=log(6\sqrt{24})\\\sqrt{24} = \sqrt{2*2*2*3} =\sqrt{2^2*6} =\sqrt{2^2} \sqrt{6}=2\sqrt{6}\\ Putting\,\,value:\\=log(6*2\sqrt{6})\\=log(12\sqrt{6})$

So, simplifying $log\sqrt{24}+log6$ we get $log(12\sqrt{6})$

Keywords: Simplifying Logarithms

Learn more about Simplifying Logarithms at:

#learnwithBrainly

3 0

3 years ago

A baseball is thrown in a parabolic arc. It's position above the ground at a given point in time can be represented by the quadr

SCORPION-xisa [38]

Answer:

The baseball reached 9 feet high above the ground

Step-by-step explanation:

The given quadratic function representing the position of the baseball above ground is p(t) = 1/2·g·t² + v₀·t + p₀

Where;

t ≥ 0

g = -32 ft./sec²

v₀ = The initial velocity

p₀ = The initial position

Given that when the ball is thrown, we have;

The initial, straight up, velocity, v₀ = 16 ft./sec

The initial position, p₀ = 5 ft.

Substituting the above values in the quadratic function representing the position of the baseball above ground, we have;

p(t) = 1/2·(-32)·t² + 16·t + 5 = 16·t - 16·t² + 5

At the maximum point, the rate of change of the height with time = 0, therefore;

dp(t)/dt = 0 = d(16·t - 16·t² + 5)/dt = 16 - 32·t

16 - 32·t = 0

16 = 32·t

t = 16/32 = 0.5 seconds

Therefore, the time takes to reach the maximum height = 0.5 seconds

The height (maximum) reached in 0.5 seconds is given as follows;

h(t) = 16·t - 16·t² + 5, from which we have;

h(0.5) = 16 × 0.5 - 16 × (0.5)² + 5 = 9

Therefore, the height baseball reached = 9 ft. above ground

7 0

2 years ago