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3 years ago

5

A 7 kilogram cat is resting on top of a bookshelf that is 3 meters high. What is the cat’s gravitational potential energy relati

ve to the floor?

1 answer:

Natalija [7]3 years ago

8 0

Gravitational potential energy stored in cat= mgh ( m= mass of cat, h = height of cat from ground) = 7x9.8x3 = 205.8 J

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The wavelength of a water wave is 6 cm when the frequency is 10 hertz .

dedylja [7]

The distance between successive crests (or successive troughs) is defined as the wavelength. The time elapsed between the crossings of two successive crests through a given point is the period of the wave.
The Velocity of propagation (Vp) of a cable is the speed at which an electrical signal can propagate through the cable in comparison to the speed of light. For example, in a vacuum, the velocity of propagation would be 100% or 1 (depending on how it is represented).
The wave period is the time it takes to complete one cycle. The standard unit of a wave period is in seconds, and it is inversely proportional to the frequency of a wave, which is the number of cycles of waves that occur in one second.

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3 years ago

A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the

alex41 [277]

Answer:

(a) $v_1 = a_1t_1 = 1.76 t_1$

(b) It won't hit

(c) 110 m

Explanation:

(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1

$v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1$

(b) The velocity of the car before the driver begins braking is

$v_1 = 1.76*20 = 35.2m/s$

The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

$a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2$

We can use the following equation of motion to calculate how far the car has travel since braking to stop

$s_2 = v_1t_2 + a_2t_2^2/2$

$s_2 = 35.2*5 - 7.04*5^2/2 = 88 m$

Also the distance from start to where the driver starts braking is

$s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352$

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

(c) The distance from the limb to where the car stops is 550 - 440 = 110 m

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3 years ago

The space between molecules is called what? Need this for a test

alexdok [17]

Answer:

voids

Explanation:

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3 years ago

A simple pendulum 2 m long swings through a maximum angle of 30 ? with the vertical.

Alexus [3.1K]

The complete question was calculate the period T assuming the smallest amplitude.
Using the equation;
T = 2 π√(L/g)
Where T is the period in seconds, L is the length of the rod or wire in meters and g is the acceleration due to gravity.
Hence; T = 2×3.14 × √(2/9.81)
= 6.28 × 0.4515
= 2.836 seconds

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4 years ago

A cloud is drifting across the sky at a constant velocity of 724metersperminute to the east. It is at an altitude of 9,200 meter

alisha [4.7K]

Answer:

The cloud moves 9050 meters to the east in 12.5 minutes.

Explanation:

Let suppose that mass of the cloud is negligible. meaning that effects of gravity are negligible and that altitude of the cloud remains constant. If the cloud drifts at constant velocity, travelled distance is defined by following formula:

$\Delta s = v\cdot \Delta t$ (1)

Where:

$v$ - Velocity, in meters per second.

$\Delta t$ - Time, in seconds.

If we know that $v = 724\,\frac{m}{min}$ and $\Delta t = 12.5\,min$ , then the travelled distance after 12.5 minutes is:

$\Delta s = 9050\,m$

The cloud moves 9050 meters to the east in 12.5 minutes.

7 0

3 years ago