Answer:
The magnitude of magnetic field at given point = × T
Explanation:
Given :
Current passing through both wires = 5.0 A
Separation between both wires = 8.0 cm
We have to find magnetic field at a point which is 5 cm from any of wires.
From biot savert law,
We know the magnetic field due to long parallel wires.
⇒
Where magnetic field due to long wires, , perpendicular distance from wire to given point
From any one wire 5 cm, 3 cm
so we write,
∴
Therefore, the magnitude of magnetic field at given point =
Period of months where the weather is the coldest and the days are the shortest.
Answer:
A copper wire current consists of electrons appropriately called conduction electrons.
Explanation:
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Answer: 2. 2.0*10^2 W
Explanation:
Power = Work/Time
Power = (2.0*10^3) Joules/10 seconds
Power = 2.0*10^2 Watts
it can be said that the speed of the east wind is
v=0.3608m/s
From the question we are told
A small boat sailed <u>straight </u>north out of a harbor in <em>strong </em>east wind (blowing from west to east).
After sailing for 120 minutes, it ended up hitting a buoy 60^\circ60 ∘ to the north-east of the harbor. If the straight-line distance between the buoy and the harbor is 3 km,
- what is the speed of the east wind?.
<h3> the speed of the east wind</h3>
Generally the equation for the distance is mathematically given as
BA=3000sin60
BA=2598.07m
Therefore
the speed of the east wind
v=0.3608
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