Answer:
It's centripetal acceleration is 301.7 m/s²
Explanation:
The formula to be used here is that of the centripetal acceleration which is
ac = rω²
where ac is the centripetal acceleration = ?
ω is the angular velocity = 3 revolutions per second is to be converted to radian per second: 3 × 2π = 3 × 2 × 3.14 = 18.84 rad/s
r is the radius = 0.85 m
ac = 0.85 × 18.84²
ac = 301.7 m/s²
It's centripetal acceleration is 301.7 m/s²
Answer:
Explanation:
Given
speed of Electron 
final speed of Electron 
distance traveled 
using equation of motion

where v=Final velocity
u=initial velocity
a=acceleration
s=displacement


acceleration is given by 
where q=charge of electron
m=mass of electron
E=electric Field strength

Answer:
7.99 or 8 depends where you round.
Explanation:
Distance divided by time so 1246/156=7.98717948718
Is the variable you change, independent, I, something I change.
Answer:
Explanation:
The work required to push will be equal to work done by friction . Let d be the displacement required .
force of friction = mg x μ where m is mass of the suitcase , μ be the coefficient of friction
work done by force of friction
mg x μ x d = 660
80 x 9.8 x .272 x d = 660
d = 3 .1 m .