Answer:
83%
Explanation:
On the surface, the weight is:
W = GMm / R²
where G is the gravitational constant, M is the mass of the Earth, m is the mass of the shuttle, and R is the radius of the Earth.
In orbit, the weight is:
w = GMm / (R+h)²
where h is the height of the shuttle above the surface of the Earth.
The ratio is:
w/W = R² / (R+h)²
w/W = (R / (R+h))²
Given that R = 6.4×10⁶ m and h = 6.3×10⁵ m:
w/W = (6.4×10⁶ / 7.03×10⁶)²
w/W = 0.83
The shuttle in orbit retains 83% of its weight on Earth.
Answer:
The new period will be √6 *T
Explanation:
period ,T=2π√(L/g) ................equation 1
where T is the period on earth
gravitational acceleration on the moon is g/6
T1 = 2π√[L/(g/6)]
T1=2π√(6L/g) ...............equation 2
divide equation 2 by 1
T1/T =2π√(6L/g)÷2π√(L/g)
T1/T =√(6L/L)
T1/T =√6
T1 = √6 *T
Answer:
the rate of turn at any airspeed is dependent upon the horizontal lift component
Answer:
101397.16 pa
Explanation:
The pressure recorded will be equal to pgh
Where p = density of mercury = 13.6x10^3 kg/m^ 3
g = acceleration due to gravity 9.81 m/s^2
h = height of mercury in the column = 760 mm = 760x10^-3 m
Pressure = 13.6x10^3 x 9.81 x 760x10^-3 = 101397.16 pa
The horizontal force Superman must apply to throw the boulder is 3670N.
According to Newton's Second law of motion,
Force F = Mass m * Acceleration a
We know that Weight W = Mass m * Gravity g
Given,
Weight W = 2400 N
Acceleration a = 15 m/
Gravitational force g = 9.81 m/
W = m * g
Mass m = 2400 / 9.81 = 244.65 kg
Horizontal force F = 244.65 * 15 = 3669.7 N
Newton's Second law of motion states that acceleration of an object depends on force acting on the object and mass of the object.
Therefore the horizontal force Superman must apply to throw the boulder is 3670N.
To know more about horizontal force
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