Answer:
Explanation:
We are given that
Charge=q=
Potential difference=V=3 V
We know that
Work done=
Using the formula
Work done by charge to move from the negative terminal to the positive terminal of battery= J
Work done by charge to move from the negative terminal to the positive terminal of battery=
Answer:
Explanation:
<u>Center of Gravity
</u>
It refers to a point where all the forces of gravity of a body make a zero total torque. To find the solution we use the fact that the net force acting on the system boat-man is in every moment equal to zero. It's assured by the first Newton’s law, the center of gravity is at rest or in uniform motion in both moments. From an external viewer's point of view, the center of gravity remains unchanged. The formula to compute it is shown below
Originally, the man sits on the stern of the boat. His weight is applied at a distance xm=4.9 m from the pier (assumed as x=0). The boat is assumed to have a uniformly distributed mass applied at its center, i.e. at xb = 4.9 / 2 = 2.45 m. The center of gravity is located originally at
When the man walks to the prow, the boat moves x = 1.2 m from the pier, so its center is located at a distance
The man is located at
The center of gravity is computed now as
Both centers of gravity are equal, thus
Simplifying
Rearranging
Thus
Hello there.
<span>The diagram shows the relative wavelengths for several types of electromagnetic energy.
Which type of electromagnetic energy has a shorter wavelength than ultraviolet waves?
Answer: </span><span>x rays
</span>
Answer:
w = w₀ / 2 the angular velocity is half the initial value.
Explanation:
We can analyze this exercise as if we added another disk to obtain a disk with twice the mass, for which if the system is two disks, the angular tidal wave is conserved
initial instant.
L₀ = I₀ w₀
final moment
L_f = I w
the moment is preserved
L₀ = L_f
I₀ w₀ = I w
the moment of inertia of a disk is
I = ½ m R²
we substitute
½ m R² w₀ = ½ (2m) R² w
w = w₀ / 2
for the case of a disk with twice the mass, the angular velocity is half the initial value.
Answer:
67000N
Explanation:
We solve for the acceleration using the the 3rd constant-acceleration equation.
(Vx)f² = (Vx)i² + 2ax∆x
We have the displacement to be
∆x = Xf - Xi = 940m
Vx = 70m/s
The acceleration = (70m/s)²/2(940m)
= 4900/1880
= 2.61m/s²
From isaac newton's second law,
51000kg x 2.61m/s²
= 133,000N
The engines thrust is half of this value
Therefore thrust = 67000N or 67kN