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Lera25 [3.4K]
3 years ago
15

The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as , where a

nd is the least intense sound a human ear can hear. Jessica is listening to soft music at a sound intensity level of 10-9 on her computer while she does her homework. Braylee is completing her homework while listening to very loud music at a sound intensity level of 10-3 on her headphones. How many times louder is Braylee’s music than Jessica’s? times louder 3 times louder 30 times louder 90 times louder
Physics
1 answer:
Misha Larkins [42]3 years ago
6 0

Answer:

3 times louder

Explanation:

The Loudness in decibel Db  L = 10㏒(I/I₀)  where I = sound intensity level and I₀ = threshold of hearing = 10⁻¹² W/m².

Now, for Jessica, I₁ = sound intensity level of Jessica's music = 10⁻⁹

and I₂ = sound intensity level of Braylee's music = 10⁻³

So, substituting the variables into the equation, we have

L₁ = 10㏒(I₁/I₀)

L₁ = 10㏒(10⁻⁹/10⁻¹²)

L₁ = 10㏒(10³)

L₁ = 3 × 10㏒10

L₁ = 30㏒10

L₁ = 30 dB

Now, for Braylee, I₂ = sound intensity level of Braylee's music = 10⁻³

So, substituting the variables into the equation, we have

L₂ = 10㏒(I₁/I₀)

L₂ = 10㏒(10⁻³/10⁻¹²)

L₂ = 10㏒(10⁹)

L₂ = 9 × 10㏒10

L₂ =90㏒10

L₂ = 90 dB

So, the number of times Braylee's music is louder than Jessica's music is L₂/L₁ = 90 dB/30 dB = 3

So, Braylee's music is 3 times louder than Jessica's music

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a bullet moving with a velocity of 100m/s pierce a block of wood and moves out with a velocityof 10 m/s.if the thickness of the
erma4kov [3.2K]

The emerging velocity of the bullet is <u>71 m/s.</u>

The bullet of mass <em>m</em> moving with a velocity <em>u</em>  has kinetic energy. When it pierces the block of wood, the block exerts a force of friction on the bullet. As the bullet passes through the block, work is done against the resistive forces exerted on the bullet by the block. This results in the reduction of the bullet's kinetic energy. The bullet has a speed <em>v</em> when it emerges from the block.

If the block exerts a resistive force <em>F</em> on the bullet and the thickness of the block is <em>x</em> then, the work done by the resistive force is given by,

W=Fx

This is equal to the change in the bullet's kinetic energy.

W=Fx=\frac{1}{2} m(u^2-v^2)......(1)

If the thickness of the block is reduced by one-half, the bullet emerges out with a velocity v<em>₁.</em>

Assuming the same resistive forces to act on the bullet,

F(\frac{x}{2} )=\frac{1}{2} m(u^2-v_1^2)......(2)

Divide equation (2) by equation (1) and simplify for v<em>₁.</em>

\frac{\frac{Fx}{2} }{Fx} =\frac{(u^2-v_1^2)}{(u^2-v^2)} \\\frac{100^2-v_1^2}{100^2-10^2} =\frac{1}{2} \\v_1^2=5050\\v_1=71.06 m/s

Thus the speed of the bullet is 71 m/s


3 0
3 years ago
A loaf of bread weighs 1362 g. The weight in kilograms is
Whitepunk [10]
The answer is d. i hope this helps :D
8 0
3 years ago
A ball is thrown horizontally at 25.8m/s from 54 meter high cliff. How far from the base of the cliff does the ball land?
mario62 [17]

Answer:

85.66m

Explanation:

Given the following data;

Horizontal velocity = 25.8m/s

Height = 54m

Initial velocity = 0

We would first of all, solve for the time taken using the formula for maximum height of a projectile.

H = ½gt²

Where;

  • H is the maximum height measured in meters.
  • g represents the acceleration due to gravity measured in meters per seconds square.
  • t represents the time taken measured in seconds.

We know that acceleration due to gravity is 9.8m/s²

Substituting into the equation

54 = ½*9.8t²

54 = 4.9t²

t² = 54/4.9

t² = 11.02

t = 3.32 secs

To find the distance;

Distance, x = velocity * time

x = vt

Substituting into the equation, we have;

x = 25.8*3.32

x = 85.66m

3 0
3 years ago
The diagram below shows the layers of a rock having a trilobite. which statement about the rock fossils is true?
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Actually the greatest information we can extract from the graph is that the lower the fossil is located beneath the rock, the older it is. So we can see that fossil A is the oldest, trilobite and fossil B came together, and fossil C is the youngest. From the choices, the answer is:

 

D. fossil B belongs to the same period as the trilobite

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4 years ago
Which values are equivalent to the fraction below ? check all that apply. 2^4/2^7
Irina18 [472]
2^4/2^7 = 16/128 = 0.125
(1/2)^3= 0.125
1/8= 0.125
a and f are equivalent
5 0
3 years ago
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