<h3>
Answer: 2p + 3q</h3>
Work Shown:
log(200) = log(2^3*5^2)
log(200) = log(2^3) + log(5^2)
log(200) = 3*log(2) + 2*log(5)
log(200) = 3*q + 2*p
log(200) = 2p + 3q
The log rules I used were
log(A*B) = log(A)+log(B)
log(A^B) = B*log(A)
Answer:
Step-by-step explanation:
Use synthetic division to answer this. If the remainder is zero, then we can safely assume the divisor (x + 7) is a factor of the polynomial f(x)= x^3-3x^2+2x-8.
We use -7 as the divisor in synth. div. This comes from the factor (x + 7):
-7 / 1 3 2 -8
-7 28 -210
-------------------------
1 -4 30 -218
Here, the remainder is -218, not zero, so no, (x+7) is not a factor of f(x)= x^3-3x^2+2x-8.
let x = a number
difference means that its subtraction
twice a number is 2x
so the equation should be
2x-5=3
add 5 to both sides
2x=8
divide both sides by 2
x=4
3/8 because there are 3 numbers you want to land on and 8 total numbers.
They are both $104.00 because you need the.40 cents to be .50 to be higher and lower
