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mylen [45]
3 years ago
11

What is the molarity of a solution containing 5.0 moles of kcl in 2.0 l of solution?

Chemistry
2 answers:
AnnyKZ [126]3 years ago
5 0

Molarity is defined as number of moles of solute dissolved per litre of solution. M is the symbol used for it. unit is= mol/ Litre  Given: Moles of solute KCl is 5 volume of solution is 2L Calculation: Molarity= Moles of Solute/ volume  M= 5/2= 2.5 mol/L

natima [27]3 years ago
4 0

Solution:

Molarity describes the concentration of a substance as measured by the number of moles divided by the volume of the solution it's in.  

Now,

We have given that

5.0 moles of kcl  

2.0 liters of solution

We have to find the concentration;

Concentration = Moles of solute divided by Volume of solution

                      = 5.0mole/2.0L

                      =2.mol/L


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You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the
Makovka662 [10]

The empirical formula of this compound is Fe_2O_3

<h3>Empirical formula </h3>

To calculate the empirical formula of a compound, the value of moles of each element is needed.

As we have the information of the mass value, we will use the molar mass expression, which corresponds to:

MM_O = 16g/mol\\MM_Fe = 55.8g/mol

                                              MM = \frac{m}{mol}

  • O

                                                   16 = \frac{4.8}{x}

                                                   x = 0.3mol

  • Fe

                                                    55.8=\frac{11.2}{x}\\x = 0.2

As the value of the empirical formula must be an integer, simply multiply the two values ​​by a common factor:

                                                O = 0.3 \times 10 = 3\\Fe = 0.2 \times 10 = 2

                                                       Fe_2O_3

So, the empirical formula of this compound is Fe_2O_3.

Learn more about empirical formula: brainly.com/question/1247523

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anzhelika [568]

Answer:

the answer is calcium

Explanation:

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