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Oduvanchick [21]
3 years ago
8

Which feature do prokaryotic and eukaryotic cells share?

Biology
1 answer:
slava [35]3 years ago
6 0
B.cytoplasm thats the answer

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A functional or physiological adaptation:
nika2105 [10]

Answer:

A trust me.

Explanation:

are you functional adaption is an adaption that helps an organism survive in a certain environment, typically altered by a physical stimuli, dietary changes, or injury.

3 0
2 years ago
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What are three meathods of CO2 transport in the blood?
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The three methods of carbon dioxide transport in the blood are dissolution in blood plasma, binding to hemoglobin, and carried in the form of bicarbonate. About 7% of the carbon dioxide is dissolved in the blood plasma. The majority of the remaining 93% is carried as part of the bicarbonate buffer system while the rest binds to hemoglobin.
7 0
3 years ago
Changes in membrane potential serve as signals to cells within the body – and can often be a drug target in the treatment of man
Vedmedyk [2.9K]

Answer:

    The membrane is actually semi-permeable.

Explanation:

    The membrane being semi-permeable means that, not all the things come in and out of the cell, only if it's really needed. The cell works in a gradient way, and that means that, to balance things, the cell will put in it a substance in a very high concentration outside of it, just to balance things. And this would happen to potassium, the cell would put it inside to balance this gradient, and once all sides have the same amount of potassium, it will stop, and the gradient is finally equal.

6 0
3 years ago
You are a botanist looking at the plant color in a new breed of Snapdragon. The two parent plants are Blue and Green and when yo
irakobra [83]

Answer:

Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.

Given:

R1R1 = 42

R2R2 = 39

R1R2 = 86

Total R1 alleles = 2*42+86 = 170

Total R2 alleles = 2*39+86 = 164

Total alleles = 334

Frequency of allele R1 = 170/334 = 0.51

Frequency of allele R2 = 164 / 334 = 0.49

Expected number of each phenotype:

Total population = 167

Blue = R1R1 = 0.51 * 0.51 * 167 = 43.44

Green = R2R2 = 0.49 * 0.49 * 167 = 40.10

Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46

Phenotype     Observed(O)    Expected (E)    O-E      (O-E)2     (O-E)2/E

Blue                 42                   43.44               -1.44       2.0736     0.0477

cyan                86                   83.46                 2.54     6.4516     0.0773

green              39                    40.1                    -1.1       1.2100      0.0302

Total              167                     167                                               0.1552

Chi-square value = 0.155

Degrees of freedom = no. of phenotypes – 1

Df = 3-1 = 2

Critical value = 5.99

Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.

4 0
3 years ago
A(n) _____________________ occurs when a clot breaks free from an artery wall and travels through the circulatory system until i
Brut [27]
An embolus <span>occurs when a clot breaks free from an artery wall and travels through the circulatory system until it lodges in a small artery and suddenly shuts off blood flow to the tissues.​</span>
4 0
3 years ago
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