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ella [17]
3 years ago
8

Is there a difference between a homogeneous mixture of hydrogen and oxygen in a 2:1 ratio and a sample of water vapor?

Chemistry
1 answer:
Feliz [49]3 years ago
5 0

Answer:

Yes

Explanation:

There is a difference between the homogeneous mixture of the hydrogen and the oxygen in a 2:1 ratio and the sample of the water vapor.

In the homogeneous mixture of the hydrogen and the oxygen which are present in the ratio, 2:1 , the elements are not chemically combined. They are explosive also as both shows their specific properties. They can be separated by physical means (Condensation, diffusion).

On the other hand, in water vapor, the two elements are chemically bonded in a specific mixture which cannot be separated via physical means. Water has its unique properties and they can be separated by chemical means only.

You might be interested in
Aspartame is a sweetner that is 160 times sweeter than sucrose (table sugar) when dissolved in water. The molecular formula of a
NikAS [45]

Answer:

  • <u><em>294.307 g/mol</em></u>

Explanation:

The first question for this statment is:

  • <em>Calculate the gram-formula-mass of aspartame. </em>

<em />

<h2>Solution</h2>

The chemical formula is:

        C_{14}H_{18}N_2O_5 .

The <em>gram-formula-mass </em>is calculated adding the masses for all the atoms in the molecular formula:

Atom       Number of atoms      Atomic mass       Total mass

                                                            g/mol            g/mol

C                     14                              12.011              14 × 12.011 = 164.154

H                     18                              1.008              18 × 1.008 = 18.144

N                      2                              14.007             2 × 14.007 = 28.014

O                      5                              15.999             5 × 15.999 = 79.995

                                                                                ===================

                                                            Total            294.307 g/mol

Answer: 294.307 g/mol

6 0
3 years ago
How many grams of HNO3 are produced when 60.0 g of NO2 completely reacts?
olganol [36]
<h3>Answer:</h3>

54.756 g

<h3>Explanation:</h3>

Assuming the equation for the reaction in question;

3NO₂(g) + H₂O(l) → 2HNO₃(aq) + NO(g)

We are given;

  • Mass of NO₂ as 60.0 g

We are required to calculate the mass of HNO₃ produced

  • We can calculate the mass of HNO₃ produced using the following simple steps;
<h3>Step 1: Calculate the moles of NO₂</h3>

Moles = Mass ÷ Molar mass

Molar mass of NO₂ = 46.01 g/mol

Therefore;

Moles of NO₂ = 60.0 g ÷ 46.01 g/mol

                       = 1.304 moles

<h3>Step 2: Calculate the moles of HNO₃ produced </h3>

From the equation, 3 moles of NO₂ reacted to produce 2 mole of HNO₃

Therefore, the mole ratio of NO₂ to HNO₃ is 3 : 2

Thus;

Moles of HNO₃ = Moles of NO₂ × 2/3

                          = 1.304 moles × 2/3

                          = 0.869 Moles

<h3>Step 3: Calculate the mass of HNO₃</h3>

Mass = Moles × Molar mass

Molar mass of HNO₃ = 63.01 g/mol

Therefore;

Mass = 0.869 moles × 63.01 g/mol

         = 54.756 g

Thus, the mass of HNO₃ produced is 54.756 g

3 0
3 years ago
State the five the five basic assumptions of the kinetic-molecular theory.
Ivan

Answer:

The primary assumptions are as follows:

Any gas is a collection of innumerable number of minuscule particles which are known as molecules according to Avogadro’s law.

There are no forces of attraction or repulsion among the particles or between the molecules and the surroundings.

The gas particles are always at straight, rapid, fast & random motion resulting in inevitable collisions with other particles and the surroundings that changes direction of motion.

Since the particle are spherical, solid and elastic the collisions involving them are elastic in nature as well i.e their kinetic energy is conserved even after collisions.

The total kinetic energy of the particles is proportional to the absolute temperature.

In some books two other assumptions are given as well:

1. The size or area of each particle is negligible compared to that of the container.

2. Pressure of gas is result of the continuous clash of the particles with the wall of the container.

or

The simplest kinetic model is based on the assumptions that: (1) the gas is composed of a large number of identical molecules moving in random directions, separated by distances that are large compared with their size; (2) the molecules undergo perfectly elastic collisions (no energy loss) with each other and with the walls of the container, but otherwise do not interact; and (3) the transfer of kinetic energy between molecules is heat. These simplifying assumptions bring the characteristics of gases within the range of mathematical treatment.

Such a model describes a perfect gas and is a reasonable approximation to a real gas, particularly in the limit of extreme dilution and high temperature. Such a simplified description, however, is not sufficiently precise to account for the behaviour of gases at high densities.

Based on the kinetic theory, pressure on the container walls can be quantitatively attributed to random collisions of molecules the average energy of which depends upon the gas temperature. The gas pressure can therefore be related directly to temperature and density. Many other gross properties of the gas can be derived, such as viscosity, thermal and electrical conductivity, diffusion, heat capacity, and mobility. In order to explain observed deviations from perfect gas behaviour, such as condensation, the assumptions must be appropriately modified. In doing so, considerable insight has been gained as to the nature of molecular dynamics and interactions.

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%5Clarge%20%5Cgreen%7B%5Cunderbrace%7B%5Cred%7BQuestion%7D%7D%7D%3A" id="TexFormula1" tit
Lesechka [4]

Answer:

Transition elements are elements which have partially filled d-orbitals and form at least one or more stable ions.

6 0
3 years ago
When 21.45 g of KNO3 was dissolved in water in a calorimeter, the temperature fell from 25.00°C to 14.14 °C. If the heat capacit
pashok25 [27]

25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)

<h3>Explanation</h3>

The process:

\text{KNO}_3\;(s) \to \text{KNO}_3\;(aq).

How many moles of this process?

Relative atomic mass from a modern periodic table:

  • K: 39.098;
  • N: 14.007;
  • O: 15.999.

Molar mass of \text{KNO}_3:

M(\text{KNO}_3) = 39.098 + 14.007 + 3\times 15.999 = 101.102\;\text{g}\cdot\text{mol}^{-1}.

Number of moles of the process = Number of moles of \text{KNO}_3 dissolved:

\displaystyle n = \frac{m}{M} = \frac{21.45}{101.102} = 0.212162\;\text{mol}.

What's the enthalpy change of this process?

Q = C\cdot \Delta T = 0.505 \times (25.00 - 14.14) = 5.4843\;\text{kJ} for 0.212162\;\text{mol}. By convention, the enthalpy change \Delta H measures the energy change for each mole of a process.

\displaystyle \Delta H = \frac{Q}{n} = \frac{5.4843\text{kJ}}{0.212162\;\text{mol}} = 25.8\;\text{kJ}\cdot\text{mol}^{-1}.

The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

4 0
3 years ago
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