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KiRa [710]
3 years ago
9

Elements that can be described by the hardness shininess and ductility

Chemistry
1 answer:
Eddi Din [679]3 years ago
6 0
Metals. Titanium is very hard, gold is shiny, and copper is ductile(can be pulled into a wire without breaking). <span />
You might be interested in
How much heat must be removed from 456 g of water at 25. 0 c to hcange it into ice at 10 c
ValentinkaMS [17]

The heat required to convert water is given as the product of the mas and the latent heat. 28.34 kJ heat must be removed from the water to change it into ice.

<h3>What is heat energy?</h3>

Heat energy is the product of mass, specific heat capacity, and temperature change. It is given as,

\rm Q = mc \Delta T

Given,

Mass of water = 456 gm

Specific heat capacity = 4.186 J / g K

Temperatutre change = 14.85 K

Substituting values above:

\begin{aligned} \rm Q &= 456 \times 4.186 \times 14.85\\\\&= 28345.91\;\rm J\\\\&= 28.34\;\rm kJ\end{aligned}

Therefore, 28.34 kJ of heat energy should be removed from the water.

Learn more about the heat here:

brainly.com/question/14052023

#SPJ4

6 0
3 years ago
What is the total number of Joules of heat absorbed by 65.0 grams of water when the temperature of the water is raised from 25°C
Norma-Jean [14]

Answer:

Total number of heat absorbed is 4.08kJ

Explanation:

Explanation is contained in the picture attached

5 0
3 years ago
Al2(CO3)3
Alborosie

Answer:

7. 6 atoms po

Explanation:

sana makatulong po

3 0
3 years ago
4. Calculate the final concentration if water is added to 1.5 L of a 12 M
konstantin123 [22]

Answer:

6M

Explanation:

(Molarity x Volume)concentrated soln = (Molarity x Volume)diluted doln

Molarity dilute soln = [(M x V)conc/V (dilute)] = 1.5L x 12M / 3.0L = 6M final dilute soln

6 0
4 years ago
A 40.0-L sample of fluorine is heated from 90.0°C to 186.0°C. What volume will the sample occupy at the higher temperature?
jasenka [17]

Answer:

The volume will be 82.67 L

Explanation:

Charles's Law is the relationship between the volume and temperature of a certain amount of ideal gas. In this way, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T} = k

Having a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

\frac{V1}{T1} =\frac{V2}{T2}

In this case, you know:

  • V1= 40 L
  • T1= 90 °C
  • V2= ?
  • T2= 186 °C

Replacing:

\frac{40L}{90C} =\frac{V2}{186 C}

Solving:

V2=\frac{40L}{90C} *186 C

V2= 82.67 L

<u><em>The volume will be 82.67 L</em></u>

5 0
4 years ago
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