What trend does the reactivity of nonmetals show in a periodic table? random changes without any trends on the periodic table ch
2 answers:
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Answer:
(a) 98.548 mPa
(b) N = 942346
9.42 X 10∧5 cycles
Explanation:
The solved solution is in the attach document.
1) The coefficient of static friction is 0.935
2) The coefficient of kinetic friction is 0.765
Explanation:
1)
When a force is applied on a box sitting on the floor, the force that must be applied in order to make the box moving is equal to the maximum force of static friction between the floor and the box, which is:
where
is the coefficient of static friction
m is the mass of the box
g is the acceleration of gravity
Here we have:
m = 30 kg
F = 275 N
Therefore, the coefficient of static friction is
2)
Once the box is in motion, the force that must be applied in order to make the box moving at constant velocity is equal to the force of kinetic friction between the floor and the box, which is:
where
is the coefficient of kinetic friction
m is the mass of the box
g is the acceleration of gravity
Here we have:
m = 30 kg
F = 225 N
Therefore, the coefficient of kinetic friction is
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The magnitude of the magnetic force per unit length on the top wire is
2×10⁻⁵ N/m
<h3>How can we calculate the magnitude of the magnetic force per unit length on the top wire ?</h3>To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula
F=
Here we are given,
= magnetic permeability
= 4×10⁻⁷ H m⁻¹
If= 12 A
d= distance from each wire to point.
=0.12m
Now we put the known values in the above equation, we get
F=
Or, F =
Or, F= 2×10⁻⁵ N/m.
From the above calculation, we can conclude that the magnitude of the magnetic force per unit length on the top wire is 2×10⁻⁵ N/m.
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