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kipiarov [429]
3 years ago
6

Natalie opened a bank account that earns 2.5% simple interest. If her account earned $180 over ten years, how much was Natalie's

initial deposit when she opened the account?
A. $0.45
B. $108
C. $720
D. $7200
Mathematics
2 answers:
Rom4ik [11]3 years ago
8 0
The answer is C, 720
Alekssandra [29.7K]3 years ago
6 0
C. Is the correct answer
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The perimeter of a rectangle is 24 inches. Find the dimensions if it’s length is 3 inches greater than its width?
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Answer:

Length: 9 inches

Width: 3 inches

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Find the slope of the line that passes through the points (3,6) and (5, 3).<br> -3/2<br> 3/2<br> 2/3
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Answer:

-3/2.

Step-by-step explanation:

To find the slope, we find the rise over run.

In this case, the rise is 6 - 3 = 3.

The run is 3 - 5 = -2.

The slope is 3 / (-2) = -3/2.

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businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
The formula for the volume, V, of a cone having the radius, r, and the height, h, is shown below. V=1/3πR^H Write the formula to
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