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earnstyle [38]
4 years ago
5

30 Points! Please Help.

Chemistry
2 answers:
DENIUS [597]4 years ago
6 0

Answer: The mass of 1 mole of Al_2O_3 is 101.96 amu.

Explanation:

Al_2O_3 is a compound. One mole of a compound has a mass which is equal to the molecular weight (molar mass) of the compound expressed in 'amu' and it contains 6.022\times 10{23} molecules of that compound.

To calculate the molar mass of the compound, we multiply the number of atoms of an element with its atomic mass. Molar mass of Al_2O_3 will be:

Atomic mass of Aluminium = 26.98 amu

Number of atoms of Aluminium = 2

Atomic mass of Oxygen = 16.00 amu

Number of atoms of Oxygen = 3

Molecular weight of Al_2O_3 = [(2\times 26.98)+(3\times 16.00)] = 101.96 amu

Hence, the mass of 1 mole of Al_2O_3 is 101.96 amu.

Nat2105 [25]4 years ago
5 0
40.08 is the answer to your questions
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What volume of hydrogen will be produced at STP by the reaction of 67.3 g of tin with excess water according to the following re
VikaD [51]

Answer:

Sn + 2H2O ==> Sn(OH)2 + 2H2

67.3 g Sn x 1 mol/119 g x 2 mol H2/mol Sn x 22.4 L/mole = answer in liters

Explanation:

Sn + 2H2O ==> Sn(OH)2 + 2H2

67.3 g Sn x 1 mol/119 g x 2 mol H2/mol Sn x 22.4 L/mole = answer in liters

5 0
3 years ago
Which member of the alkali metals has the highest
natulia [17]

Answer:

E)Li

Explanation:

Electronegativity is the tendency of an atom to attract a pair of bonding electrons. In the periodic table, electronegativity increases across the period and decrease down the group.

This means the element at the top of the group would have the highest electronegativity.

The correct option is;

E)Li

7 0
3 years ago
How many grams of water are produced when 2.50 mol oxygen reacts with hydrogen?
natali 33 [55]
I think the answer is D
4 0
3 years ago
How many moles of oxygen are needed to react with 87 grams of aluminum
labwork [276]

Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

4Al(s)  + 3O₂(l)   → 2AlO₃(s)

Given data:

Mass of aluminium = 87 g

Moles of oxygen needed = ?

Solution:

Moles of aluminium:

Number of moles of aluminium= Mass/ molar mass

Number of moles of aluminium= 87 g/ 27 g/mol

Number of moles of aluminium= 3.2 mol

Now we will compare the moles of aluminium with oxygen.

                              Al         :         O₂

                               4          :         3

                               3.2       :         3/4×3.2 = 2.4 mol

2.4 moles of oxygen are needed to react with 87 g of aluminium.

5 0
3 years ago
Will marks brainly if it isn’t a copied answer!!!
Neporo4naja [7]

What kind of control like scientific?

5 0
3 years ago
Read 2 more answers
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