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Inessa05 [86]
4 years ago
13

The diagram below shows the forces acting on a box. Describe the motion of the box. Calculate all forces

Physics
1 answer:
DanielleElmas [232]4 years ago
8 0
There'd be a force of 10N going in that > direction. This is because the top 50 and bottom 50 would cancel each other out and the 50 on the right would cancel out 50 of the 60, leaving 10. Idk if you need this but the acceleration would be the force dived end by the mass so 10/40 = 0.25 Acceleration = 0.25
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This problem has been solved! See the answer A 6.0 kg object, initially at rest in free space, "explodes" into three segments of
Monica [59]

Answer:

Explanation:

mass of each part = 6 / 3 = 2 kg .

momentum of each of given part = 2 x 20 = 40 kg m/s

Two momentum of 40 kg m/s , acting at angle 60 degree .

Resultant momentum =  2 x 40 cos 30 = 69.28 kg m/s

The third mass will have equal and opposite momentum to this momentum , following law of conservation of momentum .

If its velocity be v .

2 x v = 69.28

v = 34.64 m /s

Third mass will have velocity of 34.64 m /s

Total kinetic energy of all three mass

KE = 1/2 x 2 ( 20² + 20² + 34.64² )

= 400 + 400 + 1199.92

= 1999.93 J .

5 0
3 years ago
If a.b= 0 what is the angle between a and b​
Vlad1618 [11]

Answer:

π/2 (90°)

Explanation:

The dot product of two vectors equals the product of their magnitudes and the cosine of the angle between them.

a·b = ||a|| ||b|| cos θ

If the dot product is 0:

0 = ||a|| ||b|| cos θ

0 = cos θ

θ = π/2

The angle between a and b is π/2 (90°).

6 0
3 years ago
A current can be produced in a coil of wire _____.
mariarad [96]

Answer:

the answer is d

Explanation:

6 0
3 years ago
Which Best describes a characteristic of the jet stream?
Ipatiy [6.2K]

Answer:

Im acually a pilot and i do not know this that well, but it was to do with the atmosphere

Explanation:

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3 years ago
Two circular loops carry identical currents, but the radius of one loop is twice that of the other.
Valentin [98]

The magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.

Explanation:

The magnetic field strength at the center of a current-carrying circular loop is

B=\frac{\mu_0 I}{2R}

where

\mu_0 is the vacuum permeability

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For the first circular loop, we have

B_1 = \frac{\mu_0 I_1}{2R_1}

The second loop has

I_2 = I_1 (same current)

R_2 = 2R_1 (twice the radius)

So, the magnetic field at the centre of the second loop is

B_2 = \frac{\mu_0 I_2}{2R_2}=\frac{1}{2}(\frac{\mu_0 I_1}{2R_1})=\frac{B_1}{2}

So, the magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.

Learn more about magnetic fields:

brainly.com/question/3874443

brainly.com/question/4240735

#LearnwithBrainly

4 0
3 years ago
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