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scZoUnD [109]
3 years ago
13

A simple pendulum is hollow from within and its time period is T. how is the time period of pendulum affected when:

Physics
1 answer:
goblinko [34]3 years ago
3 0

The period of a pendulum is independent of the mass of the bob so whether it's empty or filled with something, the period remains the same.

period = 2\pi \sqrt{ \frac{length}{g} }

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A nautical mile is 6076 feet, and 1 knot is a unit of speed equal to 1 nautical mile/hour. How fast is a boat going 8 knots goin
mezya [45]

Answer:

The speed of the boat is equal to 13.50 ft/s.

Explanation:

given,

1  nautical mile = 6076 ft

1 knot = 1 nautical mile /hour

1 knot = 6076 ft/hr

speed of boat = 8 knots

 8 knots = 8 nautical mile /hour

               =8 \times \dfrac{6076\ ft}{1\nautical\ mile}\times \dfrac{1\ hour}{60\times 60\ s}

               = 13.50 ft/s

The speed of the boat is equal to 13.50 ft/s.

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3 years ago
How is Newton’s first law demonstrated by your zip line
Nikitich [7]

Newton's First Law: An object in motion stays in motion, an object at rest stays at rest unless an unbalanced force acts upon it. For example, when zipping down the zip line you will stay in motion unless an outside force interferes. ... The more mass the more force needed.

4 0
3 years ago
Which section (A or B) of the roller coaster shows positive acceleration?
Step2247 [10]

It is (A) for the first one and (B) for the second one.

6 0
4 years ago
Read 2 more answers
If an individual exercised by riding a bike with a friend for 30 minutes on a flat trail and they were engaged in a conversation
Anna35 [415]

Answer:

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Explanation:

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7 0
3 years ago
You are presented with several wires made of the same conducting material. The radius and drift speed are given for each wire in
jekas [21]

\begin{array}{ccc}&\text{Radius} & \text{Drift Speed}\\d) & 2 \; r &2.5 \; v\\a) & 3 \; r &1 \; v\\b) & 4 \; r &0.5 \; v\\c) & 1 \; r &5 \; v\\\end{array}

<h3>Explanation</h3>

I = v \cdot A \cdot n \cdot q,

where

  • I is the current;
  • v is the drift speed;
  • A is the cross-section area of the wire,
  • n is the number of charge carrier per unit volume, and
  • q is the charge on each charge carrier.

Area of a circular cross-section:

A = \pi \cdot r^{2},

where

  • r is the radius of the wire.

n and q are the same for all four samples, for they are made out of the same material.

As a result, I of each wire is directly proportional to v \cdot r^{2} where the value of \pi \cdot n \cdot q is constant.

For each of the four wires:

\begin{array}{ccc|c}\\& r & v &I \propto v\cdot r^{2}\\a) & 3 & 1 & 9\\b) & 4 & 0.5 & 8\\c) & 1 & 5 & 5\\d) & 2 & 2.5 & 10\\\end{array}.

How do the four wires rank by their current?

d > a > b > c.

3 0
4 years ago
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