Answer:
See explanation
Explanation:
To do this, you need to use energy conservation. The sum of kinetic and potential energies is the same at all points along the path so, you can write the expression like this:
1/2mv1² + mgh1 = (1/2)mv2² + mgh2
Where:
v1 = 0 because it's released from rest
h1 = 18.6 m
v2 = speed we want to solve.
h2 = height at point A. In this case, you are not providing the picture or data, so, I'm going to suppose a theorical data to solve this. Let's say h2 it's 12 m.
Now, let's replace the data in the above expression (assuming h2 = 12 m). Also, remember that we don't have the mass of the bead, but we don't need it to solve it, because it's simplified by the equation, therefore the final expression is:
1/2v1² + gh1 = 1/2v2² + gh2
Replacing the data we have:
1/2*(0) + 9.8*18.6 = 1/2v² + 9.8*12
182.28 = 117.6 + 1/2v²
182.28 - 117.6 = v²/2
64.68 * 2 = v²
v = √129.36
v = 11.37 m/s
Now, remember that you are not providing the picture to see exactly the value of height at point A. With that picture, just replace the value in this procedure, and you'll get an accurate result.
