Question

A pilot flying low and slow drops a weight; it takes 2.0 s to hit the ground, during which it travels a horizontal distance of 190 m . now the pilot does a run at the same height but twice the speed. how much time does it take the weight to hit the ground?

Answer 1

Answer:

2 s

Explanation:

when an object drops from a helicopter which is moving horizontally, the time taken by the weight to reach the ground depends on the height from which it is falling and the vertical velocity of the weight.

In both the cases, the height from which it falls is same and the vertical velocity is zero, so the time taken in both the cases is same.

Thus, the time taken by the weight to hit the ground when the pilot fly with the twice the speed is same as 2 s.

Answer 2

time taken by the object dropped = 2s

this time depends on the height of the plane from ground

it is given by

$h = \frac{1}{2} gt^2$

now the distance covered horizontally is given as 190 m

now the speed of the object is

$v = \frac{190}{2} = 95 m/s$

now when plane is moving at same height but with double speed

so it will take same time to hit the ground again

so the time is given as

$t = 2 s$

so it will take t = 2 s again to hit the ground