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Tamiku [17]
3 years ago
15

Help with number 10 please

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0

Answer:

If he is traveling over 85 miles its cheaper to use company a

Step-by-step explanation:

137-65= 72

72÷0.85= 84.7058823529= 85

So after 85 miles company A is cheaper

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For the function y = 9x, what is the output value if 5 is the input value?
vichka [17]

Answer:

45

Step-by-step explanation:

y=9x

y=9(5)

y=45

6 0
3 years ago
Q). The sum of four consecutive natural numbers is 166. What are the numbers? ​
MariettaO [177]

Answer:

see that attachment

I hope it's help you

7 0
2 years ago
Read 2 more answers
Find the circumference of a circle with the area of 95.03 m<br><br><img src="https://tex.z-dn.net/?f=c%20%3D%202%5Cpi%20%5C%3A%2
Anna [14]
We know that
[area of a circle]=pi*r²---------> r=√[area/pi]
for 
A=95.03 m²
 r=√[95.03/pi]--------> r=5.50 m

[circumference]=2*pi*r------> 2*pi*5.5--------> 34.56 m

the answer is
34.56 m
8 0
4 years ago
Does anybody know how to determine the angle again? of Q.B
Nastasia [14]

Answer:

Therefore the measur angle ACB

m\angle ACB=61.93\°

Step-by-step explanation:

Given:

ΔABC is a right Triangle at ∠A = 90°

AB = 15    ....Side Opposite to ∠ACB

AC = 8     ....Side Adjacent to ∠ACB

To Find:

m∠ACB = ?

Solution:

In Right Angle Triangle ABC, Tangent Identity we have

\tan (\angle ACB) = \dfrac{\textrm{side opposite to angle ACB}}{\textrm{side adjacent to angle ACB}}

Substituting the values we get

\tan (\angle ACB) = \dfrac{AB}{AC}=\dfrac{15}{8}=1.875\\\\\angle ACB=\tan^{-1}(1.875)\\m\angle ACB=61.93\°

Therefore the measur angle ACB

m\angle ACB=61.93\°

7 0
4 years ago
Does anyone know the answer to this question ​
Ivanshal [37]
$265.32

r = R/100
r = 4/100
r = 0.04 rate per year,
A = P(1 + r/n)nt
A = 1,000.00(1 + 0.04/1)(1)(6)
A = 1,000.00(1 + 0.04)(6)
A = $1,265.32
1,265.32-1,000=265.32
7 0
3 years ago
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