Answer:
work is shown and pictured
Answer:
2
Step-by-step explanation:
The "average value of function f(x) on interval [a, b] is given by:
f(b) - f(a)
ave. value = ---------------
b - a
Here f(t)=(t-2)^2.
Thus, f(b) = (b - 2)^2. For b = 6, we get:
f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16
For a = 0, we get:
f(0) = (0 - 2)^2 = 4
Plugging these results into the ave. value function shown above, we get:
16 - 4
ave. value = ------------ = 12/6 = 2
6 - 0
The average value of the function f(t)=(t-2)^2 on [0,6] is 2.
Answer:
A.) 1764π ft3.
Step-by-step explanation:
Volume = π r^2 h
= 14^2 * 9 * π
= 196*9 * π
= 1764 π ft3.
L’ (4.5,0) J’(-4.5, -4.5) K’(-4.5,4.5) i think
Answer:(x+1)(x+14)
Step-by-step explanation:
