This will increase the concentration of [OH-] ions.
For example:
- Ammonia NH3 (base):
NH3(aq) + H2O (l) → NH4+ + OH-
and
-NaOH:
NaOH(s) + H2O(l) → Na+ + OH-
and KOH:
KOH(s) → K+(aq) + OH-(aq)
So we can see that the base increase the [OH-] & increase the characteristic anion [OH-] of the solvent.
Explanation:
First, let's rewrite the equation here:
4 NH3 + 6 NO -> 5 N2 + 6 H2O.
The equation tells us that 6 moles of NO produces 5 moles of N2.
But the question wants us to find the quantity in grams of NO required if we have 121 g of N2.
1. So first, let's transform 121 g of N2 into moles, using its molar mass (28 g/mol) and the following formula: moles = mass/molar mass
2. Then, we use the equation ratio between NO and N2: 6:5.
3. Then we transform the result into grams of NO, using its molar mass (30.01 g/mol) and the following formula: mass = moles*molar mass
1. moles = 121/28
moles = 4.3 moles of N2
2. 6 moles of NO --- 5 moles of N2
x moles of NO --- 4.3 moles of N2
5x = 4.3*6
x = 25.9/5
x = 5.2 moles of NO
3. mass = 5.2*30.01
mass = 155.6 g
Answer: It will require 155.6 g of NO.
3) 60
4) 0.5 ("L" represent the avogadro's constant)
How do the number of electrons in the second energy shell of an atom change going across period 2 in the periodic table?
The answer is: A. The number of electrons increases by 1, from left to right.
B is wrong because atoms in period 2 DO have a second energy shell. For C, the number of electrons in the second energy shell is NOT full. For D, it is wrong to state that the number of electrons increases by 1, from right to left.
