A substance that forms a vapor is generally in what physical state at room temperature? A gas b liquid c liquid or solid d solid

There are two steps in the extraction of copper metal from chalcocite, a copper ore. In the first step, copper(I) sulfide and ox

maxonik [38]

Answer:

2Cu2S + 3O2 + 2C -------> 4Cu + 2SO2 + 2CO

Explanation:

Equation 1 should correctly be written as;

2Cu2S + 3O2-----> 2Cu2O + 2SO2

Equation 2 should be correctly written as;

2Cu2O + 2C -----> 4Cu + 2CO

The overall reaction equation is;

2Cu2S + 3O2 + 2C -------> 4Cu + 2SO2 + 2CO

Note that species that are intermediates are cancelled out .

4 0

3 years ago

Please help with this lab !

vekshin1

To get out the iron filings put everything in to a container and then put the magnet to the side to attract them. Pull them out of the container. Then, I don’t know how to separate the sand and salt. Maybe evaporate the salt? I joke you can figure it out. Best of luck! :)

4 0

3 years ago

Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What

coldgirl [10]

Answer:

$\rm_{90}^{231}\text{Th}$

Explanation:

The unbalanced nuclear equation is

$\rm _{92}^{235}\text{U} \longrightarrow \, _{2}^{4}\text{He} + X$

Let's write X as a nuclear symbol.

$\rm _{92}^{235}\text{U} \longrightarrow \, _{2}^{4}\text{He} + _{Z}^{A}\text{X}$

The main point to remember in balancing nuclear equations is that the sums of the superscripts and of the subscripts must be the same on each side of the reaction arrow.

Then

235 = 4 + A , so A = 235 - 4 = 231, and

92 = 2 + Z , so Z = 92 - 2 = 90

And your nuclear equation becomes

$\rm _{92}^{235}\text{U} \longrightarrow \, _{2}^{4}\text{He} +\, _{90}^{231}\text{X}$

Element 90 is thorium, so

$\rm X = _{90}^{231}\text{Th}$

7 0

3 years ago

A laboratory experiment requires 4.8 l of a 2.5 m solution of sulfuric acid (h2so4), but the only available h2so4 is a 6.0 m sto

Airida [17]

To determine the amount of 6.0 M H2SO4 needed for the preparation, equate the number of moles of the 6.0 M and 2.5 M H2SO4 solution. This is done as follows

M1 x V1 = M2 x V2

Substituting the known variables,

(6.0 M) x V1 = (2.5 M) x (4.8 L)

Solving for V1 gives an answer of V1 = 2 L. Thus, to prepare the needed solution, dilute 2 L of 6.0 M H2SO4 solution with water until the volume reach 4.8 L.

5 0

3 years ago

Read 2 more answers

Identify the brønsted base in the forward reaction hpo2− 4 (aq) + hno3(aq) ⇀↽ no− 3 (aq) + h2po− 4 (aq). 1. h2po− 4 (aq) 2. hno3

Simora [160]

According to Bronsted theory of acid and base, an acid in a proton donor while base is a proton acceptor. Acid donates the proton to form conjugate base, while base accepts proton to form corresponding conjugate acid.

For the reaction,
<span>hpo2− 4 (aq) + hno3(aq) </span>⇔<span> no− 3 (aq) + h2po− 4 (aq)

In above forward reaction, hno3 donotes proton to form no-3, hence no-3 is a conjugate base. </span>

3 0

3 years ago