Answer:
Acceleration of the object will be
Explanation:
We have given mass of the object m = 9 kg
spring constant k = 95 N/m
Spring is stretched by 10 cm
So x = 10 cm = 0.1 m
We know that force is given by
From newton's law we also know that force is given by
F = ma , here m is mass and a is acceleration
So
Answer:
h≅ 58 m
Explanation:
GIVEN:
mass of rocket M= 62,000 kg
fuel consumption rate = 150 kg/s
velocity of exhaust gases v= 6000 m/s
Now thrust = rate of fuel consumption×velocity of exhaust gases
=6000 × 150 = 900000 N
now to need calculate time t = amount of fuel consumed÷ rate
= 744/150= 4.96 sec
applying newton's law
M×a= thrust - Mg
62000 a=900000- 62000×9.8
acceleration a= 4.71 m/s^2
its height after 744 kg of its total fuel load has been consumed
h= 58.012 m
h≅ 58 m