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3 years ago

URGENT!!!!!

Physics

1 answer:

Dennis_Churaev [7]3 years ago

7 0

Answer:

$t = \sqrt(2h/g)$

$ax = F/m$

$x=\frac{Fh}{mg}$

$a=\sqrt(F^2/m^ + g^2)$

(a)

$t = \sqrt\frac{2h}{g+{Fsin\theta}{m}}$

(b)

$ax= \frac{Fcos\theta}{m}$

(c)

$x=\frac{hFcos\theta}{m(g+\frac{Fsin\theta}{m}}$

(d)

$a=\sqrt((\frac{F^2cos^2\theta}{m^2}+(g+\frac{Fsin\theta}{m})^2)$

Explanation:

$h = 0.5gt^2$

Therefore, $t = \sqrt(2h/g)$

$ax = \frac{F}{m}$

(3)

$x = 0.5axt^2 = \frac{0.5F/m}{2h/g} = \frac{Fh}{mg}$

(4)

$a = \sqrt(ax^2 + g^2) = \sqrt(F^2/m^ + g^2)$

(a)

$h=0.5(g+\frac{Fsin\theta}{m}$

$t = \sqrt\frac{2h}{g+{Fsin\theta}{m}}$

(b)

$ax= \frac{Fcos\theta}{m}$

(c)

$x=0.5axt^2$

$x= 0.5\frac{Fcos\theta}{m}t^2$

$x=\frac{hFcos\theta}{m(g+\frac{Fsin\theta}{m}}$

(d)

$a=sqrt(ax^2+ay^2)=\sqrt((\frac{F^2cos^2\theta}{m^2}+(g+\frac{Fsin\theta}{m})^2)$

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Answer:

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Answer:

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