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frez [133]
3 years ago
6

URGENT!!!!!

Physics
1 answer:
Dennis_Churaev [7]3 years ago
7 0

Answer:

1.

t = \sqrt(2h/g)

2.

ax = F/m

3.

x=\frac{Fh}{mg}

4.

a=\sqrt(F^2/m^ + g^2)

5.

(a)

t = \sqrt\frac{2h}{g+{Fsin\theta}{m}}

(b)

ax= \frac{Fcos\theta}{m}

(c)

x=\frac{hFcos\theta}{m(g+\frac{Fsin\theta}{m}}

(d)

a=\sqrt((\frac{F^2cos^2\theta}{m^2}+(g+\frac{Fsin\theta}{m})^2)

Explanation:

1.

h = 0.5gt^2

Therefore, t = \sqrt(2h/g)

2.

ax = \frac{F}{m}

(3)

x = 0.5axt^2 = \frac{0.5F/m}{2h/g}  = \frac{Fh}{mg}

(4)

a = \sqrt(ax^2 + g^2) = \sqrt(F^2/m^ + g^2)

5

(a)

h=0.5(g+\frac{Fsin\theta}{m}

t = \sqrt\frac{2h}{g+{Fsin\theta}{m}}

(b)

ax= \frac{Fcos\theta}{m}

(c)

x=0.5axt^2

x= 0.5\frac{Fcos\theta}{m}t^2

x=\frac{hFcos\theta}{m(g+\frac{Fsin\theta}{m}}

(d)

a=sqrt(ax^2+ay^2)=\sqrt((\frac{F^2cos^2\theta}{m^2}+(g+\frac{Fsin\theta}{m})^2)

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Answer:

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