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Luba_88 [7]
2 years ago
12

A block rests on a 15.0° incline. If the block weighs 70. N, what is the normal force on the block?

Physics
1 answer:
MissTica2 years ago
3 0

The normal force on the block at the given inclined plane is 67.61 N.

The given parameters:

  • Inclination of the plane, θ =  15.0°
  • Weight of the block, W = 70 N

<h3>What is Normal force?</h3>

The normal force on object is the upward force on the object due to its weight acting downwards.

The normal force on the block is calculated as follows;

Fₙ = mgcosθ

Fₙ = Wcosθ

Fₙ = 70 x cos(15)

Fₙ = 67.61 N

Thus, the normal force on the block at the given inclined plane is 67.61 N.

Learn more about normal force here: brainly.com/question/14486416

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You throw a ball downward from a window at a speed of 2.5 m/s. how fast will it be moving when it hits the sidewalk 2.1 m below?
Otrada [13]
List out all the variables that you do know; 

acceleration=-9.8 ms⁻¹ (this remains constant on Earth)
Final velocity=?
Displacement (s)= -2.1 m 
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v²=u²+2as 
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v²=47.41 
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Hope I helped :) 
4 0
3 years ago
Why does the cyclist have less kinetic energy at position A than at position B?
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Suppose that the cyclist begins his journey from the rest from the top of a wedge with a slope of a degree above the horizontal.
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 For energy conservation we have:
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A cardboard box sits on top of a concrete sidewalk where the coefficient of friction between the surfaces is 0.4. The mass of th
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Answer:

Fg = 98.1 [N]; N = 98.1 [N]; Ff = 39.24 [N]; a = 2.076[m/^2]

Explanation:

To solve this problem, we must make a free body diagram and interpret each of the forces acting on the box. In the attached diagram we can find the free body diagram.

The gravitational force is equal to:

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Now by summing forces on the Y axis equal to zero, we can find the normal force exerted by the surface.

N - Fg = 0

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Ff = 39.24 [N]

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60 - Ff = m * a

60 - 39.24 = 10 * a

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