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Here are 5 examples of suspensions mixtures:
<span>1-mercury shaken in oil</span>
<span>2-oil shaken in water</span>
<span>3-powdered chalk in water </span>
<span>4-dust in air</span>
<span><span>5-soot in air</span></span>
<span><span>hope this helps
</span></span>
Answer: 0.53g
Explanation:
No of moles= volume ×molarity/1000
We have the volume and the molarity
Volume=4L
Molarity=1.7M
No of moles = 4×1.7/1000
No of moles= 0.0068moles
Remember also that
No of moles= mass given/molar mass
Molar mass of Al(OH)3
Al= 27
O=16
H=1
Molar mass = Al+(O+H)3
Molar mass= 27+(16+1)3
Molar mass= 27+(17)3
Molar mass = 27+51
Molar mass= 78g/mol
To get the mass
Mass given = no of moles × molar mass
Mass= 0.0068×78
Mass= 0.53g
Answer: 
millimoles will be left after 2255 years.
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) 
of carbon = 5730 years
b) millimoles left after 2255 years
