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Leya [2.2K]
3 years ago
9

Which describes the products created from fission reactions? Question 3 options:

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
3 0

<u>Answer:</u> The correct answer is option A.

<u>Explanation:</u>

Nuclear fission reactions are a type of nuclear reactions in which larger nuclei breaks apart into two or more smaller fragment releasing alpha, gamma of beta particles.

There are 3 types of particles that can be released during this process:

1. Alpha particles: These particles are released when a nuclei undergoes alpha-decay process.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

2. Beta particles: These particles are released when a nuclei undergoes beta-minus decay process.

_Z^A\textrm{X}\rightarrow _{Z+1}^{A}\textrm{Y}+_{-1}^0\beta

3. Gamma radiations: these radiations are released when an unstable nuclei gives off excess energy by a process of spontaneous electromagnetic process.

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

Hence, any of these particles can be released during the process of fission reaction with smaller atoms.

Therefore, the correct answer is option A.

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What is the new volume of a balloon originally at 755 torr and 5.00 l is placed in a container in which the pressure is increase
Luba_88 [7]

Answer is: volume will be 3.97 liters.

Boyle's Law: the pressure volume law -  volume of a given amount of gas held  varies inversely with the applied pressure when the temperature and mass are constant.

p₁V₁ = p₂V₂.

p₁ = 755 torr.

V₁ = 5.00 l.

p₂ = 1.25 atm · 760 torr/atm.

p₂ = 950 torr.

755 torr · 5 l = 950 torr · V₂.

V₂ = 755 torr · 5 l / 950 torr.

V₂ =  3.97 l.

When pressure goes up, volume goes down.

When volume goes up, pressure goes down.

3 0
3 years ago
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A process at constant T and P can be described as spontaneous if ΔG &lt; 0 and nonspontaneous if ΔG &gt; 0. Over what range of t
creativ13 [48]

Answer:

Incomplete question, it is lacking the data it makes reference. The missing data from Chegg is:

                              2 SO3(g)   →          2 SO2(g) + O2(g)

ΔHf° (kJ mol-1)  -395.7                        -296.8

S° (J K-1 mol-1)  256.8                         248.2              205.1

ΔH° =  kJ

S° =  J K⁻¹

Explanation:

The method to solve this problem calls for the use of the Gibbs standard free energy change:

ΔG = ΔrxnH - TΔSrxn

We know a reaction is spontaneous when ΔG is < 0, so to answer this question we need to solve for the temperature, T, at which ΔG becomes negative.

Now as mentioned in the hint, we need to determine  ΔrxnH and ΔSrxn, which are given by

ΔrxnH = ∑ ν x ΔfHº products - ∑ ν x ΔfHº reactants

where  ν  is the stoichiometric coefficient in the balanced chemical equation.

For ΔS we have likewise

ΔrxnS =  ∑ ν x ΔSº products - ∑ ν x ΔSº reactants

Thus,

ΔrxnH(kJmol⁻¹) =  2 x (-296.8) - 2 x ( -395.7 ) = 197.8 kJ

ΔrxnS ( JK⁻¹) = 2 x 248.2 + 205.1 - 2 x 256.8 = 187.9 JK⁻¹ = 0.1879 kJK⁻¹

So ΔG kJ =  197.8 - T(0.1879)

and the reaction will become spontaneous when the term  T(0.1879)  becomes greater that 197.8,

0 = 197.8 - 0.1879 T  ⇒ T = 1052 K

so the reaction is spontaneous at temperatures greater than 1052 K (780 ºC)

4 0
3 years ago
Define internuclear distance.
kotykmax [81]
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If the reaction is at dynamic equilibrium at 500 K, which statement applies to the given chemical system?
Alenkinab [10]

The correct option is this: THE CONCENTRATION OF THE PRODUCTS AND THE REACTANTS DO NOT CHANGE.

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8 0
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CaCO3 (s) + 176 KJ à CaO (s) + CO (g)
statuscvo [17]

Answer:

its d

Explanation:

3 0
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