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xz_007 [3.2K]
3 years ago
8

Convert 533 cm/s to units of meters per minute. Show the unit analysis by dragging the conversion factors into the unit‑factor s

lots
Chemistry
1 answer:
lukranit [14]3 years ago
8 0

Answer:

319.8 m/min

Explanation:

533 cm/s

We can convert 533 cm/s to m/min by doing the following:

First, we shall convert 533 cm/s to m/s. This can be obtained as illustrated below:

Recall:

100 cm/s = 1 m/s

Therefore,

533 cm/s = 533 cm/s /100 cm/s × 1 m/s

533 cm/s = 5.33 m/s

Finally, we shall convert 5.33 m/s to m/min. This can be obtained as follow:

1 m/s = 60 m/min

Therefore,

5.33 m/s = 5.33 m/s / 1 m/s × 60 m/min

5.33 m/s = 319.8 m/min

Therefore, 533 cm/s is equivalent to 319.8 m/min

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HURRY HELP 10 POINTS ILL GOVE BRAINLIEST I HAVE TO PASS PICTURE PROVIDED
kramer

Answer:

C₃H₄O₄

Explanation:

In order to get the empirical formula of a compound, we have to follow a series of steps.

Step 1: Divide the percent by mass of each element by its atomic mass.

C: 34.6/12.01 = 2.88

H: 3.9/1.01 = 3.86

O: 61.5/16.00 = 3.84

Step 2: Divide all the numbers by the smallest one, i.e., 2.88

C: 2.88/2.88 = 1

H: 3.86/2.88 ≈ 1.34

O: 3.84/2.88 ≈ 1.33

Step 3: Multiply all the numbers by a number that makes all of them integer

C: 1 × 3 = 3

H: 1.34 × 3 = 4

O: 1.33 × 3 = 4

The empirical formula is C₃H₄O₄.

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3 years ago
Examine the drawing of a molecule. Each ring represents an atom of nitrogen (N). What's the chemical formula of this
Agata [3.3K]
You did not link an image of it so I can’t see the rings.
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Which of the following types of reproduction is most likely to result in a rapid growth in population?
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Asexual reproduction<span>
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What is the coefficient of MnO2when you balance the equation for this redox reaction? KCN( aq) + KMnO4( aq) + H2O( l) → KCNO( aq
chubhunter [2.5K]

Answer:

2MnO2 (s)

Explanation:

3KCN(aq) + 2KMnO4(aq) + 1H2O(l) → 3KCNO(aq) + 2MnO2(s) + 2KOH(aq)

Reactants:

K: 5

C: 3

N: 3

Mn: 2

O: 9

H: 2

Products:

K: 5

C: 3

N: 3

Mn: 2

O: 9

H: 2

8 0
3 years ago
Determine the mass in grams of 0.750 mol of francium.
jok3333 [9.3K]

Answer:

Mass =  167.25 g

Explanation:

Given data:

Number of moles of francium = 0.750 mol

Mass of francium = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Mass = number of moles × molar mass

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Mass =  0.750 mol × 223 g/mol

Mass =  167.25 g

5 0
3 years ago
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