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BabaBlast [244]
3 years ago
12

A wave is moving toward the shore If its frequency is 2.7 hertz, what is its wavelength? What would the correct number of signif

icant figures be?
Chemistry
1 answer:
TiliK225 [7]3 years ago
7 0
When multiplying and deviding follow the least number of sf.
since wavelength = 1/period
hence wavelength=1/2.7
=0.37 (2sf)
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Ok so simple 1Ag2O ---> 1Ag+1O2 do u understand how I got that????
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How much smaller is an electron than a proton​
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An electron is around 1800 times smaller than a proton

Explanation:

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2. ATO kg bouting ball would require what force to accelerate down an alleyway at a rate of ons?
Mars2501 [29]

Answer:

  • 2. 30N
  • 3. 5,000N
  • 4. 15 kg
  • 5. 2,800 kg

Explanation:

<em>2. A 10 kg bowling  ball would require what force to accelerate down an alleyway at a rate of 3m/s² ?</em>

Notice that I completed the question with the garbled and missing values:

<u>Data:</u>

  • F = ?
  • m = 10 kg
  • a = 3m/s²

<u />

<u>Physical principles:</u>

  • Newton's second law: F=m\times a

<u>Solution:</u>

  • Substitute and compute

        F=10kg\times 3m/s^2=30N

<em></em>

<em>3. Salty has a car that accelerates at 5 m/s². If the car has a mass of 1000 kg, how much force does the car produce?</em>

Notice that I arranged the typos.

<u />

<u>Data:</u>

  • F = ?
  • m = ?
  • a = ?

<u>Physical principles:</u>

  • Newton's second law: F=m\times a

<u>Solution:</u>

  • Substitute and compute

       F=1,000kg\times5m/s^2=5,000N

<em>4. What is the mass of a falling rock if it produces a force of 147 N?</em>

<u>Data:</u>

  • F = 147N
  • m = ?
  • a = falling rock

<u>Physical principles:</u>

  • neglecting air resistance ⇒ a = g: gravitational acceleration: 9.8m/s²
  • Newton's second law: F=m\times a

<u>Solution:</u>

  • Clear m from Newton's second law

         m=\dfrac{F}{a}

  • Substitute with F = 147 N and a = g = 9.8m/s², and compute

      m=\dfrac{147N}{9.8m/s^2}=15Kg

<em></em>

<em>5. What is the mass of a truck if it produces a force of 14,000 N while accelerating at a rate of 5 m/s²?</em>

<u>Data:</u>

  • F= 14,000N
  • m = ?
  • a =​ 5m/s²

<u>Physical principles:</u>

  • Second Newton's law: F=m\times a

<u>Solution:</u>

  • Clear m from Newton's second law

         m=\dfrac{F}{a}

  • Substitute with F = 14,000 N and a = 5m/s², and compute

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6 0
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The solution of this problem with explaining the solution?
maw [93]
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Imagine if the HCl used in this experiment was prepared at a concentration of 0.150M. Using your calculated volume of HCl neutra
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Answer:

Molarity = moles / volume

moles of HCl       =  molarity ×volume

                            =  0.0150 M × 0.08189L

                             = 0.0123mol

∴ the amount of CaCO3 neutralized by 0.0123 mole of HCl will be in 1:2 ratio.

moles of CaCO3 = 0.0123 mol of HCl× 1mol CaCO3/ 2mol HCl

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∴ the tablet has 0.00614 mol of CaCO3.

Explanation:

Step 1:

In the above-experiment problem, HCl acid solution is basically treated with CaCO3 base active in the tablet.

The mass of CaCO3 present in the tablet must be obtained in milligram (mg).

First, write down the balanced reaction between HCl and CaCO3  

2Hcl aq + CaC03 s ⇒ CaCl2 aq + H2O l + C02 g

CaCO3 and HCl react in 1:2 ratio of moles respectively.

∴ for each mole of calcium carbonate there would be twice the moles of HCl  required for neutralization.

Step 2

the volume is  81.89 mL (i.e 0.08189 L) of 0.150 M HCl neutralizes the whole tablet containing unknown amount of CaCO3.

So, the number of moles of HCl present in the taken volume is calculated

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