Answer:
The correct order of answers are: insolation, temperature, pressure, masses and water.
Explanation:
Daily, seasonal, and latitudinal changes in solar insolation affect Earth's climate systems. Latitude, elevation, and contrasts between land and ocean masses influence temperature patterns across the globe. Atmospheric circulation cells create rather stable regions of alternating high and low air pressure across latitudes. Temperature and water can be easily moved from place to place by air masses. Water movement via the hydrologic cycle strongly influences Earth's diverse climates.
Is there answer choices?
BTW the hunting of an elephants tusk and skin can put it towards extinction
Answer:
The angular velocity is 0.40090415 rad/sec.
Explanation:
Given that,
Height = 30 feet
Rotating rate =55,145 rev/day
We need to calculate the angular velocity
![1\ revolution = 2\pi](https://tex.z-dn.net/?f=1%5C%20revolution%20%3D%202%5Cpi)
So, ![1\ revolution /sec=\dfrac{2\pi}{60\times60\times24}\ rad/sec](https://tex.z-dn.net/?f=1%5C%20revolution%20%2Fsec%3D%5Cdfrac%7B2%5Cpi%7D%7B60%5Ctimes60%5Ctimes24%7D%5C%20rad%2Fsec)
![1\ revolution /sec=7.27\times10^{-6}\ rad/sec](https://tex.z-dn.net/?f=1%5C%20revolution%20%2Fsec%3D7.27%5Ctimes10%5E%7B-6%7D%5C%20rad%2Fsec)
![55,145\ revolution /sec=55,145\times7.27\times10^{-6}\ rad/sec](https://tex.z-dn.net/?f=55%2C145%5C%20revolution%20%2Fsec%3D55%2C145%5Ctimes7.27%5Ctimes10%5E%7B-6%7D%5C%20rad%2Fsec)
![55,145\ revolution /sec=0.40090415\ rad/sec](https://tex.z-dn.net/?f=55%2C145%5C%20revolution%20%2Fsec%3D0.40090415%5C%20rad%2Fsec)
Hence, The angular velocity is 0.40090415 rad/sec.
A liquid has a definite volume but takes the shape of whatever object it's in.
Brainliest please! Hope this Helps!
Answer:
The magnitude of F₁ is 3.7 times of F₂
Explanation:
Given that,
Time = 10 sec
Speed = 3.0 km/h
Speed of second tugboat = 11 km/h
We need to calculate the speed
![v_{1}=\dfrac{3.0\times10^{3}}{3600}](https://tex.z-dn.net/?f=v_%7B1%7D%3D%5Cdfrac%7B3.0%5Ctimes10%5E%7B3%7D%7D%7B3600%7D)
![v_{1}=0.833\ m/s](https://tex.z-dn.net/?f=v_%7B1%7D%3D0.833%5C%20m%2Fs)
The force F₁is constant acceleration is also a constant.
![F_{1}=ma_{1}](https://tex.z-dn.net/?f=F_%7B1%7D%3Dma_%7B1%7D)
We need to calculate the acceleration
Using formula of acceleration
![a_{1}=\dfrac{v}{t}](https://tex.z-dn.net/?f=a_%7B1%7D%3D%5Cdfrac%7Bv%7D%7Bt%7D)
![a_{1}=\dfrac{0.833}{10}](https://tex.z-dn.net/?f=a_%7B1%7D%3D%5Cdfrac%7B0.833%7D%7B10%7D)
![a_{1}=0.083\ m/s^2](https://tex.z-dn.net/?f=a_%7B1%7D%3D0.083%5C%20m%2Fs%5E2)
Similarly,
![F_{2}=ma_{2}](https://tex.z-dn.net/?f=F_%7B2%7D%3Dma_%7B2%7D)
For total force,
![F_{3}=F_{2}+F_{1}](https://tex.z-dn.net/?f=F_%7B3%7D%3DF_%7B2%7D%2BF_%7B1%7D)
![ma_{3}=ma_{2}+ma_{1}](https://tex.z-dn.net/?f=ma_%7B3%7D%3Dma_%7B2%7D%2Bma_%7B1%7D)
The speed of second tugboat is
![v=\dfrac{11\times10^{3}}{3600}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B11%5Ctimes10%5E%7B3%7D%7D%7B3600%7D)
![v=3.05\ m/s](https://tex.z-dn.net/?f=v%3D3.05%5C%20m%2Fs)
We need to calculate total acceleration
![a_{3}=\dfrac{v}{t}](https://tex.z-dn.net/?f=a_%7B3%7D%3D%5Cdfrac%7Bv%7D%7Bt%7D)
![a_{3}=\dfrac{3.05}{10}](https://tex.z-dn.net/?f=a_%7B3%7D%3D%5Cdfrac%7B3.05%7D%7B10%7D)
![a_{3}=0.305\ m/s^2](https://tex.z-dn.net/?f=a_%7B3%7D%3D0.305%5C%20m%2Fs%5E2)
We need to calculate the acceleration a₂
![0.305=a_{2}+0.083](https://tex.z-dn.net/?f=0.305%3Da_%7B2%7D%2B0.083)
![a_{2}=0.305-0.083](https://tex.z-dn.net/?f=a_%7B2%7D%3D0.305-0.083)
![a_{2}=0.222\ m/s^2](https://tex.z-dn.net/?f=a_%7B2%7D%3D0.222%5C%20m%2Fs%5E2)
We need to calculate the factor of F₁ and F₂
Dividing force F₁ by F₂
![\dfrac{F_{1}}{F_{2}}=\dfrac{m\times0.83}{m\times0.22}](https://tex.z-dn.net/?f=%5Cdfrac%7BF_%7B1%7D%7D%7BF_%7B2%7D%7D%3D%5Cdfrac%7Bm%5Ctimes0.83%7D%7Bm%5Ctimes0.22%7D)
![\dfrac{F_{1}}{F_{2}}=3.7](https://tex.z-dn.net/?f=%5Cdfrac%7BF_%7B1%7D%7D%7BF_%7B2%7D%7D%3D3.7)
![F_{1}=3.7F_{2}](https://tex.z-dn.net/?f=F_%7B1%7D%3D3.7F_%7B2%7D)
Hence, The magnitude of F₁ is 3.7 times of F₂