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4 years ago

If element X has 25 protons, how many electrons does it have?

Chemistry

2 answers:

igor_vitrenko [27]4 years ago

7 0

Im pretty sure it would also be 25

viva [34]4 years ago

6 0

For any element, the number of protons and electrons are the same. So, if element X has 25 protons, it would have 25 electrons.

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After swimming in the ocean for several hours, the swimmers noticed that their fingers appeared to be very wrinkled or shriveled

MatroZZZ [7]

<span>The answer is hypertonic. In osmosis, water molecules move from a hypotonic solution to the hypertonic solution, through a semipermeable membrane. This occurs until both solutions become isotonic relative to each other. In osmosis, only the movement of water molecules occurs since the ions are large enough to pass through the pores of the semipermeable membrane, in this case, the cell membrane. Due to loss of water in the process of osmosis, the cells in the fingers of the swimmers shrunk hence looked shriveled.</span>

5 0

3 years ago

Plz help, I will give brainliest.

baherus [9]

Answer: The value of $K_c$ is 2

Explanation:

Moles of $N_2O_4$ = 1.0 mole

Volume of solution = 1.00 L

Initial concentration of $N_2O_4$ = $\frac{1.0mol}{1.00L}=1.0M$

Equilibrium concentration of $NO_2$ = $\frac{1.0mol}{1.00L}=1.0M$

The given balanced equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initial conc. 1.0 M 0 M

At eqm. conc. (1.0-x) M (2x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

Given : 2x = 1.0

x= 0.5

Now put all the given values in this expression, we get :

$K_c=\frac{(1.0)^2}{(1.0-0.5)}$

$K_c=2$

Thus the value of $K_c$ is 2

4 0

3 years ago

You conduct an experiment that requires the creation of an ammonia solution. You do this by reacting 50.0 L of nitrogen gas with

ozzi

Answer : The molarity of the resulting ammonia solution is, 0.89 M

Explanation :

The balanced chemical reaction is:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

First we have to calculate the moles of nitrogen gas.

As we know that at STP, 1 mole of gas occupies 22.4 L volume of gas.

As, 22.4 L volume of nitrogen gas present in 1 moles of nitrogen gas

So, 50.0 L volume of nitrogen gas present in $\frac{50.0}{22.4}=2.23$ moles of nitrogen gas

Thus, the moles of nitrogen gas is 2.23 moles.

Now we have to calculate the moles of ammonia gas.

From the reaction, we conclude that

As, 1 mole of $N_2$ react to give 2 mole of $NH_3$

So, 2.23 moles of $N_2$ react to give $2.23\times 2=4.46$ moles of $NH_3$

Now we have to calculate the molarity of the resulting ammonia solution.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Moles of ammonia}}{\text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{4.46mole}{5.0L}$

$\text{Molarity}=0.89M$

Therefore, the molarity of the resulting ammonia solution is, 0.89 M

7 0

3 years ago

Where can you find atoms

Papessa [141]

Atoms make up everything, so technically--everywhere.

4 0

4 years ago

Read 2 more answers

(a) starting with solid sucrose, c12h22o11, describe how you would prepare 250 ml of a 0.250 m sucrose solution. (b) de- scribe

Anna007 [38]

a. We first calculate the moles of sucrose needed

moles sucrose = 0.250 M * 0.25 L

moles sucrose = 0.0625 mol

The molar mass of sucrose 342.3 g/mol, so the mass of sucrose needed is:

mass sucrose = 0.0625 mol * 342.3 g/mol

mass sucrose = 21.4 grams

So simply dissolved about 21.4 grams of sucrose in 250 mL solution.

b. We use the formula:

M1 V1 = M2 V2

1.50 M * V1 = 0.100 M * 0.350 L

V1 = 0.0233 L = 23.3 mL

So simply take 23.3 mL of solution from 1.50 M then dilute it with water until 350 mL to make 0.100 M.

5 0

4 years ago