Answer:
b)5l x 10kg c)10kg + 9l (Not sure for the last 1)
The answer is (3) HClO. In the Cl2, chlorine has an oxidation number of zero. In HCl, the oxidation number is -1. In HClO2, the oxidation number is +3. In HClO, it is +1. You can calculate this by using O with oxidation number of -2 and H with +1.
Answer:
Covalent bonding
Explanation:
In covalent bonding, the electrons are shared to fill the octet rule (8 electrons in valence shell). CCl4 tends to do covalent bonding because the the 4 valence electrons are Carbon are shared with the Chlorine atoms so that each chlorine atom has a full octet and chlorine shares its electrons to fill the octet of carbon.
Also, since carbon and chlorine are both non-metal, non-metal things exhibit covalent bonding thus this is covalent bonding as well. Ionic boding is for metal and non metal pair where electrons are transferrred, in our case, electrons are shared, they are not transferred.
Answer:
0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.
Explanation:
Mass percentage of oxalic acid = 5.50%
This means that in 100 grams of solution there are 5.50 grams of oxalic acid.
Mass of solution , m = 100
Volume of the solution = V
Density of the solution = d = 1.024 g/mL
![V=\frac{m}{d}=\frac{100 g}{1.024 g/mL}=97.66mL](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Bm%7D%7Bd%7D%3D%5Cfrac%7B100%20g%7D%7B1.024%20g%2FmL%7D%3D97.66mL)
V = 97.66 mL = 0.09766 L
(1 mL = 0.001 L)
Moles of oxalic acid = ![\frac{5.50 g}{90 g/mol}=0.06111 mol](https://tex.z-dn.net/?f=%5Cfrac%7B5.50%20g%7D%7B90%20g%2Fmol%7D%3D0.06111%20mol)
![Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20solute%7D%7D%7B%5Ctext%7BVolume%20of%20solution%20in%20L%7D%7D)
The molarity of the solution :
![=\frac{0.06111 mol}{0.09766 L}=0.6257M](https://tex.z-dn.net/?f=%3D%5Cfrac%7B0.06111%20mol%7D%7B0.09766%20%20L%7D%3D0.6257M)
0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.