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labwork [276]
2 years ago
6

What's the mass of methanol?

Chemistry
2 answers:
olga nikolaevna [1]2 years ago
8 0
Molar/molecular mass? methanol's chemical formula is: CH3OH . Mass of C = 12, Mass of O = 16, Mass of H = 1
So, molar mass of methanol is just a sum of masses of elements I listed above.
Mass of methanol = 12+3x1+16+1=32 (grams/mole or units)
Vikki [24]2 years ago
6 0
Methanol= CH3OH
C has an atomic mass of 12.011
H has an atomic mass of 1.007
O has an atomic mass of 16
 Multiply 1.007 x 4 = 4.028
Add 4.028 + 12.011 + 16 = 32.04 amu is your answer.
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jenyasd209 [6]
By using thermal energy which is also heat energy the substance in cup A will melt becoming a liquid behaving like the substance in cup B
5 0
2 years ago
You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute b
alexdok [17]

Answer:

             0.045 L  or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

8 0
2 years ago
Brainliest for an answer!
Degger [83]

The volume of H₂ : = 15.2208 L

<h3>Further explanation</h3>

Given

Reaction

2 As (s) + 6 NaOH (aq) → 2 Na₃AsO₃ (s) + 3 H₂ (g)

34.0g of As

Required

The volume of H₂ at STP

Solution

mol As (Ar = 75 g/mol) :

= mass : Ar

= 34 g : 75 g/mol

= 0.453 mol

From the equation, mol ratio As : H₂ = 2 : 3, so mol H₂ :

=3/2 x mol As

=3/2 x 0.453

= 0.6795

At STP, 1 mol = 22.4 L, so :

= 0.6795 x 22.4 L

= 15.2208 L

5 0
2 years ago
What is the mass of a 1.71-l sample of a liquid that has a density of 0.921g/ml?
Temka [501]
Hey there!:

Volume in mL :

1.71 L * 1000 => 1710 mL

Density = 0.921 g/mL

Therefore:


Mass = Density * Volume

Mass = 0.921 * 1710

Mass = 1574.91 g
8 0
2 years ago
In an acid-base titration, a student uses 21.35 mL of 0.150 M NaOH to neutralize 25.00 mL of H2SO4. How many moles of acid are i
GalinKa [24]

Answer: There are 0.006 moles of acid in the flask.

Explanation:

Given: V_{1} = 21.35 mL,        M_{1} = 0.150 M

V_{2} = 25.0 mL,           M_{2} = ?

Formula used to calculate molarity of H_{2}SO_{4} is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.15 M \times 21.35 mL = M_{2} \times 25.0 mL\\M_{2} = 0.1281 M

As molarity is the number of moles of a substance present in a liter of solution.

Total volume of solution = V_{1} + V_{2}

= 21.35 mL + 25.0 mL

= 46.36 mL  (1 mL = 0.001 L)

= 0.04636 L

Therefore, moles of acid required are calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\0.1281 M = \frac{no. of moles}{0.04635 L}\\no. of moles = 0.006 mol

Thus, we can conclude that there are 0.006 moles of acid in the flask.

3 0
3 years ago
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