When magnesium reacts with sulfuric acid the products are magnesium sulfate and hydrogen. If there are 15 grams of magnesium at
1 answer:
Answer: 15 grams of magnesium will be present in the magnesium sulfate
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side.
The balanced chemical reaction is:
As the mass remains conserved at the end of the reaction, there will be 15 grams of Magnesium in magnesium sulphate.
You might be interested in
Answer : The mass of sulfuric acid needed is .
Solution : Given,
pH = 8.94
Volume of solution = 380 ml =
Molar mass of sulfuric acid = 98.079 g/mole
As we know,
Now we have to calculate the moles of .
Formula used :
For neutralization, equal number of moles of ions will neutralize same number of
ions.
As,
From this reaction, we conclude that
2 moles of ion is given by the 1 mole of
moles of
ion is given by
moles of
Now we have to calculate the mass of sulfuric acid.
Mass of sulfuric acid = Moles of × Molar mass of sulfuric acid
Mass of sulfuric acid =
Therefore, the mass of sulfuric acid needed is .