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ehidna [41]
3 years ago
14

When magnesium reacts with sulfuric acid the products are magnesium sulfate and hydrogen. If there are 15 grams of magnesium at

the start of the reaction, how much magnesium will be present in the magnesium sulfate
Chemistry
1 answer:
Sergeeva-Olga [200]3 years ago
8 0

Answer: 15 grams of magnesium will be present in the magnesium sulfate

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side.

The balanced chemical reaction is:

Mg+H_2SO_4\rightarrow MgSO_4+H_2

As the mass remains conserved at the end of the reaction, there will be 15 grams of Magnesium in magnesium sulphate.

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snow_lady [41]
The answer should be granite

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6 0
3 years ago
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The United States produces thousands of different kinds of inorganic chemicals. Inorganic chemicals, for the most part, do not c
mario62 [17]

1) In order to write formulas of chemical compounds we need the periodic table to find out some oxidation numbers.

Sulfuric acid: H2SO4. This compound has a polyatomic ion called sulfate with a 2- charge. To balance those negative charges we need two H+ ions.

Nitrogen: N2

Oxygen: O2

Ammonia: NH3

Lime: CaCO3. This compound is made up of calcium (Ca2+) and a polyatomic ion called carbonate (CO3 2-). Two positive charges and two negative charges. It is balanced.

Phosphoric acid: H3PO4. This compound has a polyatomic ion called phosphate with a 3- charge. In this compound, we need 3 H+ to balance those negative charges.

Sodium hydroxide: NaOH. Hydroxide compounds have a two-part name. The name of the cation (Na+) and the name of the hydroxide (OH-). One positive charge and one negative charge. It is balanced.

Chlorine: Cl2.

Sodium carbonate: Na2CO3. This compound has a polyatomic ion called carbonate with a 2- charge. We need two positive charges to balance the compound. Sodium is in the first group in the periodic table. That means sodium has just one positive charge, so we need two sodiums.

Nitric acid: HNO3. This compound has a polyatomic ion called nitrate with a 1- charge. To balance that negative charge we need one H+ ion.

5 0
1 year ago
If the solution of HNO3 has a pH of 8 and a pOH of 6 is it an acid, base or neutral
zloy xaker [14]
I don’t know but I think the answer is C or B
4 0
3 years ago
4. Describe the arrangement of the electrons on each energy level.
never [62]

Answer:

Explanation:

If the energy of an atom is increased, an electron in the atom gets excited. To go back to its ground state, the electron releases energy. The energy of the light released when an electron drops in energy level is the same as the difference in energy between the two levels.

Viewed simply, electrons are arranged in shells around an atom’s nucleus. Electrons closest to the nucleus will have the lowest energy. Electrons further away from the nucleus will have higher energy. An atom’s electron shell can accommodate 2n2 electrons (where n is the shell level).

In a more realistic model, electrons move in atomic orbitals, or subshells. There are four different orbital shapes: s, p, d, and f. Within each shell, the s subshell is at a lower energy than the p. An orbital diagram is used to determine an atom’s electron configuration.

There are guidelines for determining the electron configuration of an atom. An electron will move to the orbital with lowest energy. Each orbital can hold only one electron pair. Electrons will separate as much as possible within a shell.

7 0
3 years ago
What happens when a metal is reduced. Give an example of a metal being reduced
AlexFokin [52]

Answer:

The oxidation number of the metal decreases

2 Al  + Fe₂O₃ → Al₂O₃ + 2 FeO

The metal element iron, is reduced from Fe⁺³ in Fe₂O₃ to Fe⁺² in FeO

Explanation:

When an element gains electron, the element becomes reduced, hence when a metal is reduced, the metal gains electrons, which reduces the oxidation number of the metal

An example of a metal being reduced is;

2 Al  + Fe₂O₃ → Al₂O₃ + 2 FeO

In the above reaction, the iron (III) oxide is reduced to iron (II) oxide by aluminium metal.

6 0
4 years ago
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