with an excess of oxygen gas according to the following chemical equation. 4 P 502 > 2 P2Os What mass of P2O5 can be produced
1 answer:
Answer:
394.76g
Explanation:
Given parameters:
Mass of Phosphorus = 172.1g
Unknown:
Mass of P₂O₅ = ?
Solution:
We should work from the known specie to the unknown in this problem. The limiting reactant is the reactant in short supply and it determines the extent of the reaction. This is the given phosphorus.
Oxygen is in the excess.
The balanced reaction equation:
4P + 5O₂ → 2P₂O₅
let us find the number of moles of phosphorus first,
Number of moles of phosphorus =
Molar mass of phosphorus = 31g/mole
Number of moles = = 5.55mole
4 moles of phosphorus gives 2 moles of P₂O₅
5.55 mole of P will produce = 2.78moles
Mass of P₂O₅ = number of moles x molar mass
Molar mass of P₂O₅ = (31 x 2) + (16 x 5) = 142g/mole
Mass of P₂O₅ = 2.78moles x 142g/mole = 394.76g
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Answer:
See explanation.
Explanation:
Hello,
In this case, we can show how the empirical formula is found by following the shown below procedure:
1. Compute the moles of carbon in carbon dioxide as the only source of carbon at the products:
2. Compute the moles of hydrogen in water as the only source of hydrogen at the products:
3. Compute the mass of oxygen by subtracting the mass of both carbon and hydrogen from the 0.4647-g sample:
4. Compute the moles of oxygen by using its molar mass:
5. Divide the moles of carbon, hydrogen and oxygen by the moles of oxygen (smallest one) to find the subscripts in the empirical formula:
6. Search for the closest whole number (in this case multiply by 2):
Moreover, the empirical formula suggests this compound could be carboxylic acid since it has two oxygen atoms, nevertheless, this is not true since the molar mass is 222.27 g/mol, therefore, we should compute the molar mass of the empirical formula, that is:
Which is about three times in the molecular formula, for that reason, the actual formula is:
It suggest that the compound has a highly oxidizing character due to the presence of oxygen, therefore, we cannot predict the distribution of the functional groups as it could contain, carboxyl, carbonyl, hydroxyl or even peroxi.
Best regards.