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3 years ago

10. Plot and connect the points to form a rectangle. Then find the length, width, and area of the rectangle.

Mathematics

1 answer:

stellarik [79]3 years ago

4 0

The length of the rectangle is 4

The width of the rectangle is 3.

The area of the rectangle is 12 square units.

Explanation:

Given that the coordinates of the rectangle are A(3,0), B(0,0), C(0,4), D(3,4)

We need to determine the length, width and area of the rectangle.

Length:

After plotting the coordinates in the graph, it is obvious that the length of the rectangle is 4.

Width:

After plotting the coordinates in the graph, it is obvious that the width of the rectangle is 3.

Area of the rectangle:

The formula to determine the area of the rectangle is given by

$Area=length \times width$

Substituting the values, we have,

$Area=4\times 3=12$

Thus, the area of the rectangle is 12 square units.

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Let X = the time between two successive arrivals at the drive-up window of a local bank. If X has an exponential distribution wi

LuckyWell [14K]

Answer:

a) E(X)=1

b) σ=1

c) P(X>1)=0.368

d) P(2<X<5)=0.128

Step-by-step explanation:

We have X: "the time between two successive arrivals at the drive-up window of a local bank", exponentially distributed with λ = 1.

a) We have to compute the expected time between two successive arrivals.

The expected value for X as it is exponentially distributed is:

$E(X)=\dfrac{1}{\lambda}=\dfrac{1}{1}=1$

b) We have to compute the standard deviation of X.

The standard deviation is calculated as:

$\sigma=\dfrac{1}{\lambda}=\dfrac{1}{1}=1$

c) The probability that X is larger than 1 (P(X>1))

We can express the probability as:

$P(X>t)=e^{-\lambda t}\\\\P(X>1)=e^{-\lambda\cdot 1}=e^{-1}=0.368$

d) The probability that X is between 2 and 5 (P(2<X<5))

$P(X>t)=e^{-\lambda t}\\\\\\P(25)\\\\P(2$

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What is a coupon on a bond similar to?

VladimirAG [237]

A coupon is a paper with a discount.

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An online spinner has two colored regions--blue and yellow. according to the website, the probability that the spinner lands in

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Step-by-step explanation:

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3 years ago

Read 2 more answers

2. The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.

Paul [167]

For this case we have an equation of the form:
h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
Where,
vo: initial speed
a: acceleration:
h0: initial height.
We have the following equation:
h (t) = - 16t2 + 19t + 110
Therefore, the initial velocity is:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown:
vo = 19 feet / s

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3 years ago

BRAINLIESTTTTTT ASAPPPP PLEASE ANSWER MY QUESTION

yawa3891 [41]

The red line is represented by y ≥ -3x + 3.

The blue line is represented by y < 3/2x - 6.

A) In this system of inequalities, there is one solid line and one dashed line.

The solid line is the inequality y ≥ -3x + 3 because it has the symbol greater than or equal to. The "equal to" part of the symbol is important because it means that any coordinate located on the solid line is a solution.

However, the inequality y < 3/2x - 6 is a dashed line because it does not have "equal to." This makes the inequality a dashed line which means that all coordinates on it will not be a solution to the inequality.

In the inequality y ≥ -3x + 3, the shading is above the line. This means that all coordinates within the line and shaded area above the line will be a solution to the inequality.

In the inequality y < 3/2x - 6, the shading is below the line. This means that all coordinates within the shared area of the line will be a solution to the inequality. However, since y is not less than or EQUAL TO, all coordinates within the dashed line is not a solution to the inequality.

The solution area, where a coordinate is a solution to
both inequalities, is where the shaded areas of both inequalities overlap.

B) The point (-6, 3) is a not solution to both of the inequalities because it is not within the shared areas of the two inequalities.

Substitute the coordinate (-6, 3) in the inequality y < 3/2x - 6.

y < 3/2x - 6

3 < 3/2(-6) - 6

3 < -9 - 6

3 < -15

This is not true because a negative number cannot be greater than a positive number. Therefore, this proves that the coordinate (-6, 3) is not a solution for the inequality y < 3/2x - 6.

Check if the coordinate fits for the other inequality.

y ≥ -3x + 3

3 ≥ -3(-6) + 3

3 ≥ 18 + 3

3 ≥ 21

This is also not true because 3 is not greater than or equal to 21. Therefore, this coordinate is not a solution to the inequality y ≥ -3x + 3.

The coordinate (-6, 3) is not a solution for the system of inequalities because it is not a solution for both inequalities.

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3 years ago