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hram777 [196]
3 years ago
14

10. Plot and connect the points to form a rectangle. Then find the length, width, and area of the rectangle.

Mathematics
1 answer:
stellarik [79]3 years ago
4 0

The length of the rectangle is 4

The width of the rectangle is 3.

The area of the rectangle is 12 square units.

Explanation:

Given that the coordinates of the rectangle are A(3,0), B(0,0), C(0,4), D(3,4)​

We need to determine the length, width and area of the rectangle.

<u>Length:</u>

After plotting the coordinates in the graph, it is obvious that the length of the rectangle is 4.

<u>Width:</u>

After plotting the coordinates in the graph, it is obvious that the width of the rectangle is 3.

<u>Area of the rectangle:</u>

The formula to determine the area of the rectangle is given by

Area=length \times width

Substituting the values, we have,

Area=4\times 3=12

Thus, the area of the rectangle is 12 square units.

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Which expression is a difference of cubes?
Tanzania [10]

Answer:

Option 4 is correct.

Step-by-step explanation:

Given the following options

we have to choose the difference of cubes.

Option 1:

9w^{33}-y^{12}

9(w^{11})^{3}-(y^4)^3

which is not the difference of cubes

Option 2:

18p^{15}-q^{21}

18(p^5)^3-(q^7)^3

which is not the difference of cubes

Option 3:

36a^{22}-b^{16}

(6a^{11})^2-(b^8)^2

which is the difference of square

Option 4:

64c^{15}-a^{27}

(4c^5)^3-(a^9)^3

which is the difference of cubes.

8 0
2 years ago
A school principal ordered 1,000 pencils.He gave an equal number to each of 7 teachers until he had given out as many as possibl
Ahat [919]
1000/7 = <span>142.857142857

Because this is not an even number we take "142", then times it by 7 teachers.

142*7= 994

1000 - 994 = 6 Pencils left</span>
3 0
3 years ago
Read 2 more answers
Explain 2 methods other than looking for intersections on the graph itself that will locate all intersections
GaryK [48]
Finding the zeros using factoring and also the discriminat
6 0
3 years ago
Kase, an individual, purchased some property in Potomac, Maryland, for $217,000 approximately 10 years ago. Kase is approached b
Advocard [28]

The question is incomplete.

The complete question is

Kase, an individual, purchased some property in Potomac, Maryland, for $217,000 approximately 10 years ago. Kase is approached by a real estate agent representing a client who would like to exchange a parcel of land in North Carolina for Kase’s Maryland property. Kase agrees to the exchange.

What is Kase’s realized gain or loss, recognized gain or loss, and basis in the North Carolina property in each of the following alternative scenarios? (Loss amounts should be indicated by a minus sign. Leave no answer blank. Enter zero if applicable.)

a. The transaction qualifies as a like-kind exchange and the fair market value of each property is $907,500.

b. The transaction qualifies as a like-kind exchange and the fair market value of each property is $199,000.

Answer:

A. Realized gain(907500-217000)= 609,500

Recognized gain= 0

Adjustment basis in new property=217,000.

B. Realised loss ( 199000 - 217000) = 18,000

Recognized loss= 0

Adjusted basis in new property= 217000

Step-by-step explanation:

A.

Realized gain(907500-217000)= 609,500

Recognized gain= 0

Adjustment basis in new property=217,000.

Here , we find that Kase has realised gain of $ 690,500 but recognised gain of $ 0 . It is so because Kase did not receive any boot and the transaction is a like-kind exchange. Therefore, the adjusted basis in new property = $ 217,000 ( as no gain is recognised ).

B.

Realised loss ( 199000 - 217000 )= 18,000

Recognized loss= 0

Adjusted basis in new property= 217000

7 0
3 years ago
The sum of three numbers is 10. Two times the second number minus the first number is equal to 12.
eimsori [14]

<u>Answer:</u>

-10,1,19

<u>Step-by-step explanation:</u>

<u></u>

x+y+z = 10 (Equation 1)

2y-x= 12  (Equation 2)

x-y+2z = 7 (Equation 3)

(Equation 2): -x = -2y+12

                       x = 2y-12 (Equation 4)

(Equation 1) - (Equation 3): 2y-z = 3

                                              -z = -2y+3

                                               z = 2y-3 (Equation 5)

Substitute (4) and (5) into (1)

x+y+z = 10

(2y-12)+y+(2y-3) = 10

5y-15 = 10

5y = 5

y=1

Substitute y=1 into (2)

2y-x= 12

2(1)-x= 12

2-x= 12

-x= 12-2

-x= 10

x= -10

Substitute y=1 and x=-10 into (1)

x+y+z = 10

-10+1+z = 10

z-9 = 10

z = 10+9

z = 19

Order: x = -10, y = 1, and z = 19

8 0
3 years ago
Read 2 more answers
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