The refrection of a point or set of points across the line y = x will result in a point or set of points whose coordinates are the interchange of the x-value and the y-value of the original point or set of points.
Given that the vertices of a triangle are P(-8, 6), Q(1, -3) and R(-6, -3), the vertices of the triangle formed by the refrection Ry=x<span>(ΔPQR) are P'(6, -8), Q'(-3, 1) and R'(-3, -6).</span>
Answer: -3g - 4
(-2g + 7) - (g + 11)
= -2g + 7 - g - 11
= -3g - 4
Step-by-step explanation:
You could have a Quadratic with 2 distinct solution meaning you have 2 different X intercepts
2 roots means the discriminan is positive in other words
D>0
When the discriminan is 0, D=0 we have exactly one x-intercept.
Discriminan D=0
and finally, if the discriminan were negative
D=0
then there is no solution or root at all.
(;-; my hand hurts)
$18 per ticket
3 baskets per minute
6 yds per attempt
dab
Where’s the graph? I will need it if I can help.
