You can start this by setting up two vectors starting at the origin.
Vector 1 has coordinates of (-57,0) since in the east direction.
Vector 2 has coordinates of (0,13) because going north.
Starting from the origin, plot the two points, which will give you two sides of a triangle.
You can use pythagorean theorem to solve for the magnitude of the velocity. And you can find the angle by arctan(y/x)
Pythagorean would produce 58.46m/s
Answer:
The speed of the wave remains the same
Explanation:
Since the speed of the wave v = √(T/μ) where T is the tension in the string and μ is the linear density of the string.
We observed that the speed, v is independent of the frequency of the wave in the string. So, increasing the frequency of the wave has no effect on the speed of the wave in the string, since the speed of the wave in the string is only dependent on the properties of the string.
<u>So, If you increase the frequency of oscillations, the speed of the wave remains the same.</u>
Answer:
A transformer is a passive electrical device that transfers electrical energy from one electrical circuit to another, or multiple circuits.
Explanation:
Hope it helps
Most likely climbing up the mountain
Answer:
Explanation:
Given;
The operational pressure of the cooker, 
area of the opening, 
- We know that the gauge pressure is measured with respect to the atmospheric pressure. As the atmospheric pressure acts on all the components of the system being observed so, we only need to counter the gauge pressure.
As the petcock sits on the opening of the cross-section so, it balances the built-in pressure due to its weight.
<u>Hence:</u>
where:
mass of the petcock
acceleration due to gravity
