Question

A sample of 5.6 L of a gas is at a pressure of 1.5 atm. If the volume of the gas is compressed to 4.8 L, what will the new pressure be

Answer 1

Answer:

1.75 atm.

Explanation:

Using Boyle's law equation of gas which states that at constant temperature, the volume of a fixed amount of gas is inversely proportional to the pressure exerted.

Mathematically,

P = kV

Given:

V1 = 5.6 l

V2 = 4.8 l

P1 = 1.5 atm

P1V1 = P2V2

P2 = P1V1/V2

= (1.5 * 5.6)/4.8

= 1.75 atm.

Answer 2

Answer:

1.75atm

Explanation:

According to Boyle's law, the pressure P of a fixed mass of gas is inversely proportional to it's volume V provided that the temperature remains constant.

$P\alpha \frac{1}{V}\\hence\\PV=constant$

This implies the following;

$P_1V_1=P_2V_2=...=P_nV_n............(1)$ Provided temperature is kept constant.

Given;

$P_1=1.5atm\\V_1=5.6L\\P_2=?\\V_2=4.8L$

From equation (1), we can write;

$P_1V_1=P_2V_2\\hence\\1.5*5.6=P_2*4.8\\\\P_2=\frac{1.5*5.6}{4.8}\\\\P_2=1.75atm$

Since all the units are consistent, there is no need for conversion.